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Angelina_Jolie [31]
3 years ago
7

How do fission nuclear reactions differ from fusion nuclear reactions? Fission reactions involve the conversion of matter into e

nergy, but fusion reactions do not. Fusion reactions involve the conversion of matter into energy, but fission reactions do not. Fission reactions are used to generate electricity for consumers, but fusion reactions are not. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.
Physics
2 answers:
MakcuM [25]3 years ago
5 0

How do fission nuclear reactions differ from fusion nuclear reactions?

A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not. 

B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not. 

C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not. 

D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.

Answer:

C

Explanation:

Both fission and fusion are nuclear reactions that produce energy, but their applications differs.

 Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.

The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.

The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.

mamaluj [8]3 years ago
3 0

Answer:

C

Explanation:

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Answer:

Maximum speed of the rod, v = 10.34 m/s

Explanation:

It is given that,

Voltage of the battery, V = 2.7 V

The magnetic field perpendicularly into the plane of the paper is, B = 0.9 T

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Due to the motion of the rails inside the magnetic field, an emf will induced in it which is given by :

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v=\dfrac{2.7}{0.9\times 0.29}

v = 10.34 m/s

So, the maximum speed attained by the rod after the switch is closed is 10.34 m/s. Hence, this is the required solution.

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ASAP When salt is dissolved in water, the result is a A. gas B. compound C. homogeneous mixture D. heterogeneous mixture
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A car is traveling at 39.7 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s 2 . If the coefficient of fricti
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Answer:

The minimum distance in which the car will stop is

x=167.38m

Explanation:

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∑F=m*a

∑F=u*m*g

The force of friction is the same value but in different direction of the force moving the car so it can stop so

F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }

a=-0.9408 \frac{m}{s^{2}}

v_{f}^{2}=v_{o}^{2}+2*a*(x_{f}-x_{o})\\v_{f}=0 \\x_{o}=0\\0=v_{o}^{2}+2*a*x_{f}\\x_{f}=\frac{v_{o}^{2}}{2*a} \\x_{f}=\frac{(-17.747\frac{m}{s})^{2}}{2*(-0.9408)} \\x_{f}=167.38m

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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
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Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

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V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

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Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately

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