1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Angelina_Jolie [31]
4 years ago
7

How do fission nuclear reactions differ from fusion nuclear reactions? Fission reactions involve the conversion of matter into e

nergy, but fusion reactions do not. Fusion reactions involve the conversion of matter into energy, but fission reactions do not. Fission reactions are used to generate electricity for consumers, but fusion reactions are not. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.
Physics
2 answers:
MakcuM [25]4 years ago
5 0

How do fission nuclear reactions differ from fusion nuclear reactions?

A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not. 

B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not. 

C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not. 

D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.

Answer:

C

Explanation:

Both fission and fusion are nuclear reactions that produce energy, but their applications differs.

 Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.

The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.

The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.

mamaluj [8]4 years ago
3 0

Answer:

C

Explanation:

You might be interested in
A convex lens of focal length 25 cm is in contact with a concave lens of focal length 50 cm. The equivalent focal length of this
Gwar [14]

The equivalent focal length of this combination-lenses should be +50 cm.

Given:

Focal length of convex lens, f₁ = +25 cm

Focal length of concave lens, f₂ = -50 cm

Calculation:

We know that the power of a lens is given as:

P = 1 / f

where, f is the focal length of lens

Now, the power of convex lens can be calculated as:

P₁ = 1/f₁

  = 1/(25×10⁻² m)

  = 100/25

  = +4 D

Similarly, the power of concave lens can be calculated as:

P₂ = 1/f₂

    = (1/-50×10⁻² m)

    = -100/50

    = -2 D

Thus, the power of the combined lenses can be calculated as:

P₍₁₊₂₎ = P₁ + P₂

       = +4 D - 2 D

       = +2 D

Now, the combined focal length of the lens can be calculated as:

f₍₁₊₂₎ = 1 / P₍₁₊₂₎

      = 100 / 2 D

      = +50 cm

Therefore, the equivalent focal length of this combination-lenses will be +50 cm.

Learn more about mirrors and lenses here:

<u>brainly.com/question/3209252</u>

#SPJ4

6 0
2 years ago
How does a dynamo Work?
marin [14]
The generator/dynamo<span> is made up of stationary magnets (stator) which create a powerful magnetic field, and a rotating magnet (rotor) which distorts and cuts through the magnetic lines of flux of the stator. When the rotor cuts through lines of magnetic flux it makes electricity.</span>
8 0
3 years ago
If a cup of coffee has temperature 95∘C95∘C in a room where the temperature is 20∘C,20∘C, then, according to Newton's Law of Coo
lina2011 [118]

Answer:

T = 76.39°C

Explanation:

given,

coffee cup temperature = 95°C

Room temperature= 20°C

expression

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

temperature at t = 0

T( 0 ) = 20 + 75 e^{\dfrac{-0}{50}}

T(0) = 95°C

temperature after half hour of cooling

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

t = 30 minutes

T( 30 ) = 20 + 75 e^{\dfrac{-30}{50}}

T( 30 ) = 20 + 75 \times 0.5488

T(30) = 61.16° C

average of first half hour will be equal to

T = \dfrac{1}{30-0}\int_0^30(20 + 75 e^{\dfrac{-t}{50}})\ dt

T = \dfrac{1}{30}[(20t - \dfrac{75 e^{\dfrac{-t}{50}}}{\dfrac{1}{50}})]_0^30

T = \dfrac{1}{30}[(20t - 3750e^{\dfrac{-t}{50}}]_0^30

T = \dfrac{1}{30}[(20\times 30 - 3750 e^{\dfrac{-30}{50}} + 3750]

T = \dfrac{1}{30}[600 - 2058.04 + 3750]

T = 76.39°C

4 0
3 years ago
A pulley with the radius of 10.0 cm was connected to a motor with a massless
kogti [31]

Answer:

(i) -556 rad/s²

(ii) 17900 revolutions

(iii) 11250 meters

(iv) -55.6 m/s²

(v) 18 seconds

Explanation:

(i) Angular acceleration is change in angular velocity over time.

α = (ω − ω₀) / t

α = (10000 − 15000) / 9

α ≈ -556 rad/s²

(ii) Constant acceleration equation:

θ = θ₀ + ω₀ t + ½ αt²

θ = 0 + (15000) (9) + ½ (-556) (9)²

θ = 112500 radians

θ ≈ 17900 revolutions

(iii) Linear displacement equals radius times angular displacement:

s = rθ

s = (0.100 m) (112500 radians)

s = 11250 meters

(iv) Linear acceleration equals radius times angular acceleration:

a = rα

a = (0.100 m) (-556 rad/s²)

a = -55.6 m/s²

(v) Angular acceleration is change in angular velocity over time.

α = (ω − ω₀) / t

-556 = (0 − 15000) / t

t = 27

t − 9 = 18 seconds

8 0
3 years ago
Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge
MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

V_1 = V_2 (1)

Keeping in mind the relationship between charge, voltage and capacitance:

C=\frac{Q}{V}

we can re-write (1) as

\frac{Q_1}{C_1}=\frac{Q_2}{C_2} (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

C=4 \pi \epsilon_0 R

where R is the radius of the sphere. Substituting this into (2), we find

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2} (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

R_2 = 2R_1

So the eq.(3) becomes

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}

And re-arranging it we find:

Q_2 = 2Q_1

And since we know that the total charge is

Q_1 + Q_2 = 7.00 nC

we find

Q_1 = 2.33 nC\\Q_2 = 4.67 nC

3 0
4 years ago
Other questions:
  • A 2.4 kg ball is thrown straight up with a speed of 35 m/s.what is its initial kinetic energy? Find the maximum height the ball
    11·1 answer
  • A baseball player runs 27.4 meters from the
    11·2 answers
  • Heat gained or lost is mass times specific heat times change in temperature.
    14·2 answers
  • An electric fence displays a warning sign about voltage and amperage of the fence. How would amperage and voltage affect the pow
    13·1 answer
  • You must push a crate across a floor to a docking bay. The crate weighs 198 N. The coefficient of static friction between crate
    14·1 answer
  • EARTH SCIENCE --the line of longitude used as the origin in a system of coordinates
    10·1 answer
  • <img src="https://tex.z-dn.net/?f=%5Chuge%20%5Cfbox%20%5Cpink%20%7Bq%7D%5Chuge%20%5Cfbox%20%5Cgreen%20%7B%CF%85%7D%5Chuge%20%5Cf
    9·2 answers
  • A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
    14·1 answer
  • A light wave has a frequency of <img src="https://tex.z-dn.net/?f=%286%20%5Ctimes%20%7B10%7D%5E%7B8%7D%29." id="TexFormula1" tit
    13·2 answers
  • Which is the example of circular motion??
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!