Reaction of
Acyl Halides with
Grignard reagent results in the formation of
Ketones in first step. While in second step reaction of Grignard reagent with Ketones results in the formation of
Tertiary Alcohols.
If you want to
stop the reaction at
Ketone stage then you are required to use another
mild reactive organometallic compound. In our case we will use Organocuprates.
Organocuprates are also known as Gilman Reagents. These reagents does not add to ketones, aldehydes and esters but they can add to acid halides to produce Ketones.
Explanation:
Lime is added to lower the acidity of lakes when pH levels go too low.
Acidic environment is harmful to aquatic ecosystems. Acidity causes some minerals, such as phosphorus and calcium, in the water to become unavailable to aquatic organisms like plants and fishes ( This means the water hardness is reduced). The low nutrients cause stress and death in the aquatic environment lowering biodiversity. Applying lime raises the pH to neutral levels and improves the health of the aquatic life in the lake. This also improves economic activities in the lake like fishing.
Learn More:
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Explanation:
According to ideal gas equation, product of pressure and volume equals the product of number of moles, gas constant and temperature.
Mathematically, PV = nRT
where P = pressure, V = volume
n = no. of moles, R = gas constant = 0.0821 atm L/mol
T = temperature
Since, it is known that number of moles equal mass divided by molar mass.
Hence, number of moles of given sample of acetone are as follows.
No. of moles = 
= 
= 
mole
Therefore, putting the values in ideal gas equation as follows.
PV = nRT
= 0.359 atm
In 1 atm equal to 760 mm Hg. So, convert 0.359 atm into mm Hg as follows.
= 272.84 mm Hg
Hence, pressure of the ideal gas will be 100 mm Hg + 272.84 mm Hg = 372.84 mm Hg
Thus, we can conclude that the ideal gas pressure in the container if all of the liquid acetone evaporated is 372.84 mm Hg.
Answer:
The correct answer is 1.778 milligrams per liter.
Explanation:
Based on the given information, the concentration of chlorine gas given is 27 pounds or 27*453.59 = 12327.93 grams.
The quantity of water given is 750000 gallons or 750000 * 3.754 = 2815500 L
The concentration of chlorine used up by the microorganism is 2.6 mg/L or 0.0026 gm/L.
Thus, for 2815500 L of water, the amount of chlorine used is,
= 2815500 * 0.0026
= 7320.3 grams
The left quantity of chlorine is 12327.93 - 7320.3 = 5007.63 grams
The concentration of residual chlorine is,
= 5007.63 g/2815500 = 0.00177859 or 1.778 mg/L.
