Answer:
False
Explanation:
Let's consider the definition of the angular momentum,
![\vec{L} = I \vec{\omega}](https://tex.z-dn.net/?f=%5Cvec%7BL%7D%20%3D%20I%20%5Cvec%7B%5Comega%7D%20)
where
is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,
so
unless
║
.
In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.
Answer:
This is known as a Galilean transformation where
V' = V - U
Where the primed frame is the Earth frame and the unprimed frame is the frame moving with respect to the moving frame
V - speed of object in the unprimed frame
U - speed of primed frame with respect to the unprimed frame
Here we have:
V = -15 m/s speed of ball in the moving frame (the truck)
U = -20 m/s speed of primed (rest) frame with respect to moving frame
So V' = -15 - (-20) = 5 m/s
It may help if you draw a vector representing the moving frame and then add
a vector representing the speed of the ball in the moving frame.
Answer:
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Answer:
given,
mass of the skier = 70.1 Kg
angle with horizontal, θ = 8.6°
magnitude of the force,F = ?
a) Applying newton's second law
velocity is constant, a = 0
![F_{rope} = m g sin\theta](https://tex.z-dn.net/?f=F_%7Brope%7D%20%3D%20m%20g%20sin%5Ctheta)
![F_{rope} = 70.1\times 9.8\times sin 8.6^0](https://tex.z-dn.net/?f=F_%7Brope%7D%20%3D%2070.1%5Ctimes%209.8%5Ctimes%20sin%208.6%5E0)
![F_{rope}= 102.73\ N](https://tex.z-dn.net/?f=F_%7Brope%7D%3D%20102.73%5C%20N)
b) now, when acceleration, a = 0.135 m/s²
velocity is constant, a = 0.135 m/s₂
![F_{rope} = m g sin\theta+ma](https://tex.z-dn.net/?f=F_%7Brope%7D%20%3D%20m%20g%20sin%5Ctheta%2Bma)
![F_{rope} = 70.1\times 9.8\times sin 8.6^0+70.1\times 0.135](https://tex.z-dn.net/?f=F_%7Brope%7D%20%3D%2070.1%5Ctimes%209.8%5Ctimes%20sin%208.6%5E0%2B70.1%5Ctimes%200.135)
![F_{rope}= 112.19\ N](https://tex.z-dn.net/?f=F_%7Brope%7D%3D%20112.19%5C%20N)
Answer:
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Explanation:
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