Need answer please help out

When of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing poi

Nesterboy [21]

The given question is incomplete. The complete question is:

When 282. g of glycine (C2H5NO2) are dissolved in 950. g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 282. g of ammonium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X.

Answer: the van't Hoff factor for ammonium chloride is 1.74

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

$K_f$ = freezing point constant = ?

i = 1 ( for non electrolyte)

m= molality

$8.2^0C=1\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (glycine) = 75.07 g/mol

Mass of solute (glycine) = 282 g

$8.2^0C=1\times K_f\times \frac{282g}{75.07g/mol\times 0.95kg}$

$K_f=2.07$

ii) $20.0^0C=i\times \times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (ammonium chloride) = 53.49 g/mol

Mass of solute (ammonium chloride) = 282 g

$20.0^0C=i\times 2.07\times \frac{282g}{53.49g/mol\times 0.95kg}$

$i=1.74$

Thus the van't Hoff factor for ammonium chloride is 1.74

4 0

3 years ago

HELPPP how many Hg grams is .25 moles of CaO??

Eva8 [605]

15.5 grams
is your anwser

6 0

4 years ago

Why does carbon form so many organic compounds?

11111nata11111 [884]

Because each carbon atom can form for chemical bonds to another’s atoms and because the carbon atom is just the right small size to fit in comfortably as parts of very large molecules

8 0

3 years ago

Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

nika2105 [10]

Answer: Reaction A: pi + glucose ⇒ glucose-6-phosphate + H2O ΔG = 13.8 kJ/mol

Reaction B: pi + frutose-6-phosphate ⇒fructose-1,6-biphosphate + H2O ΔG = 16.3kJ/mol

Explanation: ΔG is the representation of the change in Gibbs Free Energy and relates enthalpy and entropy in a single value, which is:

ΔG = ΔH - TΔS

where:

ΔH is enthalpy

T is temperature

ΔS is entropy (measure of the )

It can also predict the direction of the reaction with the conditions of temperature and pressure being constant.

When the change is positive, the reaction is non-spontaneous, which means the reaction needs external energy to occur. If the change is negative, it is spontaneous, i.e., happens without external help.

Analyzing the reaction, we see that reaction A and B have a positive ΔG, while reaction C is negative, so the reaction that are unfavorable or nonspontaneous are <u>reactions A and B</u>.

6 0

3 years ago

7. A figure skater skating across ice, who grabs another skater and brings him along the ice with her, is an example of what typ

xenn [34]

Answer:

The type of collision is A. Inelastic collision.

Explanation:

The macroscopic collisions are generally inelastic and do not conserve the kinetic energy, although of course the total energy is conserved. The inelastic collision is one in which the objects that collide remain together after the collision.

So, a figure skater skating across ice, who grabs another skater and brings him along the ice with her is a clear example of inelastic collision.

6 0

4 years ago

Read 2 more answers