Answer: 27.5 liters
Explanation:
To calculate the moles, we use the equation:
For ![KClO_3](https://tex.z-dn.net/?f=KClO_3)
Given mass = 100.0 g
Molar mass of
= 122.5 g/mol
Putting values in above equation, we get:
![\text{Moles of}KClO_3 =\frac{100}{122.5}=0.82moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7DKClO_3%20%3D%5Cfrac%7B100%7D%7B122.5%7D%3D0.82moles)
![2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)](https://tex.z-dn.net/?f=2KClO_3%28s%29%5Crightarrow%202KCl%28s%29%2B3O_2%28g%29)
2 moles of
produces 3 moles of ![O_2](https://tex.z-dn.net/?f=O_2)
0.82 moles of
produces =
moles of ![O_2](https://tex.z-dn.net/?f=O_2)
Volume of ![O_2=moles\times {\text {molar volume}}=1.23\times 22.4=27.5L](https://tex.z-dn.net/?f=O_2%3Dmoles%5Ctimes%20%7B%5Ctext%20%7Bmolar%20volume%7D%7D%3D1.23%5Ctimes%2022.4%3D27.5L)
Thus 27.5 liters of
are produced by the complete decomposition of 100.0 g of
at STP
It's metallic atomic solid as it is a kind of metal .
A. Sugar... Because the others are mixes of things and combinations. Sugar is pure and on its own.
I hope this helps!
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Hope I helped!
Answer:
Option c → 8:1
Explanation:
This is the reaction:
C₅H₁₂ + 8O₂ → 10CO₂ + 6H₂O
1 mol of pentane needs 8 moles of oxygen to be combusted and this combustion produces 10 mol of carbon dioxide and 6 moles of water.
To determine the ratio, look the stoichiometry.
For every 8 moles of oxygen, I need 1 mole of pentane gas.