Answer:
If we start with 20 atoms of plutonium – 239, how many would remain after 48,240 years?
Explanation:
So, before we are going to tackle this topic, I would discuss how to remain it as soon as possible. Like this, go to the site with so many answers to be seen. So m SC ndkz ek Afe sifrhidbjdjwsb in free jdbsjjkn WA jdj ew
I would love to help but it is 3 or is it 3 million?
Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
Explanation:
A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.
Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.
So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.
- As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

- Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

- Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
The specific heat of the unknown metal is 0.859 J/g⁰C.
<h3>Specific heat of the unknown metal</h3>
Heat lost by the unknown metal = Heat gained by water
m₁c₁Δθ₁ = m₂c₂Δθ₂
where;
- c₁ is specific heat of the unknown metal
- c₂ is specific heat of water
(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)
1095c₁ = 940.5
c₁ = 940.5/1095
c₁ = 0.859 J/g⁰C
Learn more about specific heat here: brainly.com/question/16559442
#SPJ1
Answer:
D and E
Explanation:
The other answers don't support steel, they support iron or are supporting both, and the question is why steel alloys are more often used
C supports both
B supports how iron's strength
A supports iron being easily shaped and bent
hope this helps