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3 years ago

NEED HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics

2 answers:

sladkih [1.3K]3 years ago

7 0

Answer:

the correct answer would be D. A variable or alteration to one part that affects an entire system.

the other ones dont make sense

~batmans wife dun dun dun....

frozen [14]3 years ago

5 0

It would be c repeated processes-that are used in a variety of ways

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Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position = < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack = < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

= [(-440*4) + (0*0) + (220*-2)]

= -1760 J - 440 J

= -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

= [(170*4) + (0*0) + (340*-2)]

= 680 J - 680 J

= 0

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4 years ago

Write the first equation of motion. Under what condition(s) is this equation valid?

Zepler [3.9K]

Explanation:

The first equation of motion in kinematics is given by :

$v=u+at$ .....(1)

u is initial speed

a is acceleration

v is final speed

t is time

Equation (1) is valid when the object is moving with constant acceleration. This equation gives relation between velocity and time.

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3 years ago

Convertir 500 f a grado celsios

Allushta [10]

Answer:

260° C

Explanation:

5 0

3 years ago

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If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net

DIA [1.3K]

I think you would do 20+7 = 27N as the net force

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3 years ago

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A step index fiber has a numerical aperture of NA = 0.1. The refractive index of its cladding is 1.465. What is the largest core

Vladimir [108]

Answer:

diameter = 9.951 × $10^{-6}$ m

Explanation:

given data

NA = 0.1

refractive index = 1.465

wavelength = 1.3 μm

to find out

What is the largest core diameter for which the fiber remains single-mode

solution

we know that for single mode v number is

V ≤ 2.405

and v = $\frac{2*\pi *r}{ wavelength} NA$

here r is radius

so we can say

$\frac{2*\pi *r}{ wavelength} NA$ = 2.405

put here value

$\frac{2*\pi *r}{1.3*10^{-6}} 0.1$ = 2.405

solve it we get r

r = 4.975979 × $x^{-6}$ m

so diameter is = 2 × 4.975979 × $10^{-6}$ m

diameter = 9.951 × $10^{-6}$ m

3 0

3 years ago