All categories

3 years ago

Can someone answer this for me please

Chemistry

2 answers:

Vanyuwa [196]3 years ago

5 0

Answer:

option A

hope it helps!!!!!!!!!!!!!!

Bess [88]3 years ago

4 0

Answer:

Explanation: k =10^3, m =10^-3

2.8 Kg = 2.8 *10^3 g

To conver kg to mg you need to

=2.8* 10^3 *10^-3* 10^3

=2.8 * 10^6 *10^-3

= 2.8 * 10^6 mg

You might be interested in

At archery practice, Vladimir tests a bow and arrow he has recently designed. He is able to accelerate a 24.0-g arrow at an aver

Whitepunk [10]

Answer: A

1.68 N

Explanation:

F = ma = 0.024(70.0) = 1.68 N

7 0

3 years ago

g Alkenes and alkynes are called unsaturated compounds because ________. they have fewer hydrogen atoms attached to the carbon c

Firdavs [7]

Answer:

They have fewer hydrogen atoms attached to the carbon chain than alkanes

Explanation:

Let's compare ethane (an alkane) with ethene (an alkene) and ethyne (an alkyne):

Ethane's formula is C₂H₄, while ethene's is C₂H₄ and ethyne's C₂H₂.

As you can see, alkenes and alkynes have fewer hydrogen atoms attached to the carbon chain due to them having multiple bonds between the carbon atoms.

7 0

3 years ago

What is the name given to the ions of the halogens on the periodic table?

WARRIOR [948]

Answer:

halides

Explanation:

This is one electron away from having a full octet of eight electrons, so these elements tend to form anions having -1 charges, known as halides: fluoride, F-; chloride, Cl-, bromide, Br-, and iodide, I-. In combination with other nonmetals, the halogens form compounds through covalent bonding.

7 0

3 years ago

The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and calcium chl

dsp73

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

4 0

4 years ago

The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti

nadezda [96]

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈ combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

$The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%$

The percentage yield = 83.77%.

7 0

3 years ago