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inysia [295]
4 years ago
14

Which sentence states Newton’s third law?

Physics
2 answers:
valina [46]4 years ago
8 0
B

b/c newtons third law of motion is: "For every action, there is an equal and opposite reaction."
shepuryov [24]4 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

Newton's third law states that every action has an equal and opposite reaction.

For example, when we hit a ball with the help of a bat then the ball exerts an equal and opposite force on the bat.

Thus, we can conclude that out of the given options, the sentence if two objects collide, each object exerts a force equal to and in the opposite direction of the other states Newton's third law.

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Pierre cycles at 4 miles per hour and travels a distance of 13 miles. How long
amm1812

Answer:

His journey took him 3 hours 15 minutes.

Explanation: 4 miles every hour. So 1 hr is equal to 4 miles, 2 hrs is equal to 8 miles, 3 hrs is equal to 12 miles. Now he just has 1 miles left, and since it takes him a hour to cycle 4 miles, 60 divided by 4 is 15. Therefore, 1 mile is equal to 15 minutes.

4 0
4 years ago
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An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. Calculate the centripetal acce
tekilochka [14]

Given:

Object in circular motion 25 m/s

1 second to go quarter circle

Required:

Centripetal acceleration:

Solution:

Acceleration = v2/r

Where v is the velocity and r is the radian

Substituting the values into the equation,

Acceleration = v2/r = (25 m/s)2/(4*pi/180) = 8952.47 m2/s2

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4 years ago
How can Newton's third law describe the forces affecting a rocket as it
rusak2 [61]

Answer:D

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Apex

7 0
4 years ago
What are some properties of transverse waves?
allsm [11]
They send out waves differently and cannot be heard easily
5 0
3 years ago
The nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particl
Lyrx [107]

Answer:

a)    F = 21.16 N,  b)     a = 3.17 10²⁸ m / s

Explanation:

a) The outside between the alpha particles is the electric force, given by Coulomb's law

          F = k \frac{ q_1 q_2}{r^2}

in that case the two charges are of equal magnitude

          q₁ = q₂ = 2q

let's calculate

         F = 9 \ 10^9 \ \frac{ (2 \ 1.6 \ 10^{-19} )^2 }{ (6.60 \ 10^{-15} )^2 }

         F = 21.16 N

this force is repulsive because the charges are of the same sign

b) what is the initial acceleration

         F = ma

         a = F / m

         a = \frac{21.16}{4.0026 \ 1.67 \ 10^{-27} }21.16 / 4.0025 1.67 10-27

         a = 3.17 10²⁸ m / s

this acceleration is in the direction of moving away the alpha particles

7 0
3 years ago
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