1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlabodo [156]
3 years ago
10

A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignit

e the fuel occurs because the pistons compress the air in the cylinders. Suppose that air at an initial temperature of 18° C is compressed adiabatically to a temperature of 733° C. Assume the air to be an ideal gas for which
γ = 7/5
Find the compression ratio, which is the ratio of the initial volume to the final volume.
Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Compression ratio = 24.42

Explanation:

From Thermodynamic,

Adiabatic Equation ⇒ TV^{γ-1} = Constant.

⇒T₁V₁^{γ-1}  = T₂V₂^{γ-1} ..................(1)

Where T₁= initial Temperature, V₁ = Initial Volume, T₂ = final Temperature, V₂ = Final Volume.

Given:  T₁= 18°C we convert to  Kelvin(K) by adding 273.

∴      T₁= 18°C + 273 = 291K

        T₂ = 733° C  also,we convert to  Kelvin(K) by adding 273

 ∴      T₂ = 733° C +273 =1046K

          γ = 7/5

 ∴ Rearranging equation(1), we have

    (T₁/T₂) = (V₂/V₁)^{γ-1}................(2)

also rearranging equation(2) we have

   (V₁/V₂)^{γ-1} = (T₂/T₁).

Where (V₁/V₂) = Compression ratio.

∴ (V₁/V₂)^{(7/5)-1} =( 1046/291)

simplifying the index in the equation

I.e (7/5)-1 = (7-5 )/5 = 2/5.

(V₁/V₂)^2/5 =(1046/291)^2/5

Multiplying the power on both side of the equation by 5/2.

∴(V₁/V₂)^(2/5)×(5/2) = (1046/291)^(5/2)

⇒ V₁/V₂= (1046/291)^2.5=( 3.59)^2.5

    V₁/V₂ = 24.42.

∴ Compression ratio = 24.42

You might be interested in
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
miss Akunina [59]

Formula of the gravitational force between two particles:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67 \cdot 10^{-11} Nm^2 kg^{-2} is the gravitational constant

m1 and m2 are the masses of the two particles

r is their distance


(a) particle A

The gravitational force exerted by particle B on particle A is

F_B=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=5.14 \cdot 10^{-5} N to the right

The gravitational force exerted by particle C on particle A is

F_C=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=5.6 \cdot 10^{-6} N to the right

So the net gravitational force on particle A is

F_A = F_B + F_C =5.14 \cdot 10^{-5} N+5.6 \cdot 10^{-6} N=5.7 \cdot 10^{-5} N to the right


(b) Particle B

The gravitational force exerted by particle A on particle B is

F_A=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=-5.14 \cdot 10^{-5} N to the left

The gravitational force exerted by particle C on particle B is

F_C=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=8.41 \cdot 10^{-5} N to the right

So the net gravitational force on particle B is

F_B = F_A + F_C =-5.14 \cdot 10^{-5} N+8.41 \cdot 10^{-5} N=3.27 \cdot 10^{-5} N to the right


(c) Particle C

The gravitational force exerted by particle A on particle C is

F_A=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=-5.6 \cdot 10^{-6} N to the left

The gravitational force exerted by particle B on particle C is

F_B=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=-8.41 \cdot 10^{-5} N to the left

So the net gravitational force on particle C is

F_C = F_B + F_A =-8.41 \cdot 10^{-5} N-5.6 \cdot 10^{-6} N=-8.97 \cdot 10^{-5} N to the left



3 0
3 years ago
A container of gas is held at a constant pressure. Which of these would cause both the volume of the gas and the average kinetic
Sloan [31]
The correct answer is letter B
7 0
2 years ago
Read 2 more answers
A force of 20 N acts acts on an object of 4.0 kg mass that is initially at rest. What is the resulting acceleration of the objec
ki77a [65]

Answer:

Explanation:

Acceleration = Force/ mass = 20/4 = 5 m/s².

acceleration a = 5 m/s² , initial velocity u = 0 , time t = 6 s

S = ut + 1/2 a t² = 0 + 1/2 x 5 x 6² = 90 m .

distance traveled = 90 m.

4 0
3 years ago
What is the speed of light?
amm1812
<span>299 792 458 m / s hop i helped</span>
3 0
3 years ago
Read 2 more answers
I need science fair ideas for 4th grade, But i need something that won't need a oven, sunlight, ETC. Also, i need something that
Lina20 [59]
Something simple?
Hmm, how about a diagram of a fod chain? Its simple, if you dont have a printer to print the images of a food chain, or animals, then just try to draw it the best you can...
Make it into a poster, write some information about the animals, who eats who, are they a carnivor, herbivor, you know... Stuff like that :)
~.~.~.~.~.~.~.~.
<em>Hope this helped! :)</em>
5 0
3 years ago
Other questions:
  • Determine how potential and kinetic energy changes at each position of the pendulum as the ball swings from A to E. Position A:
    10·2 answers
  • James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air-conditione
    11·1 answer
  • A uniform bar of length 3.7 m and mass 4.5 kg is attached to a wall through a hinge mechanism which allows it to rotate freely.
    14·1 answer
  • About 10% of the water in the world ocean makes up all of the surface currents. most surface currents move water above the _____
    11·1 answer
  • on june 20, 1969, two american astronauts named Buss Aldrin and Neil Armstrong became the first humans to contact the surface of
    14·1 answer
  • Two objects, X and Y, are held at rest on a horizontal frictionless surface and a spring is compressed between them. The mass of
    8·1 answer
  • Calculate the earth's average speed relative to the sun.
    15·1 answer
  • Red light Green light is used to work on what skill?
    7·2 answers
  • Screw cannot be driven if there is no force​
    6·2 answers
  • could you help with question 5. Your solutions to the word problems in volving Newton's Laws should have the following features:
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!