Answer:
Elastic Modulus = 227 GPa
Explanation:
Given,
Load = 84998 N
Length of bar = 300 mm = 0.3 m
Elongation = 0.18 mm = 0.00018 m
Cross sectional Area of the bar = (25mm × 25mm) = 0.025 × 0.025 = 0.000625 m²
From Hooke's law, the stress experienced by a material is proportional to the strain experienced by the same body, as long as the elastic limit isn't exceeded.
Stress ∝ strain
The coefficient of proportionality is the elastic modulus, E.
Stress = E × (Strain)
Stress = (Load)/(Cross sectional Area)
Stress = (84998 ÷ 0.000625) = 135,996,800 N/m²
Strain = (Change in length)/(Original length)
Strain = (ΔL/L) = 0.00018 ÷ 0.3 = 0.0006
E = (Stress/Strain)
E = 135,996,800 ÷ 0.0006 = 226,661,333,333.3 Pa = (2.267 × 10¹¹) Pa
1 GPa = 10⁹ Pa
(2.267 × 10¹¹) = 2.267 × 10² × 10⁹ = 226.7 GPa = 227 GPa to the nearest GPa. (No decimal place)
Hope this Helps!!!
