1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reil [10]
3 years ago
9

An inquisitive physics student and mountain climber climbs a 54.0-m-high cliff that overhangs a calm pool of water. He throws tw

o stones vertically downward, 1.00 s apart, and observes that they cause a single splash. The first stone has an initial speed of 1.82 m/s.
(a) How long after release of the first stone do the two stones hit the water? s
(b) What initial velocity must the second stone have if the two stones are to hit the water simultaneously? magnitude m/s direction
(c) What is the speed of each stone at the instant the two stones hit the water? first stone m/s second stone m/s
Physics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

a) After the release of the first stone the two stones hit the water at 3.14 seconds.

b)Initial velocity of second stone = 14.74 m/s

c) Speed of first stone at the instant the two stones hit the water = 32.62 m/s

Speed of second stone at the instant the two stones hit the water = 35.73 m/s

Explanation:

a) For first stone we have

  Initial velocity, u =  1.82 m/s

  Acceleration , a = 9.81 m/s²

  Displacement, s = 54 m

  We have equation of motion s= ut + 0.5 at²

 Substituting

   s= ut + 0.5 at²

    54 = 1.82 x t + 0.5 x 9.81 x t²

    4.905 t² + 1.82 t - 54 = 0

    t = 3.14 s or t = -3.51 s  (not possible)

After the release of the first stone the two stones hit the water at 3.14 seconds.

b) The second stone is thrown after 1 s

 Time taken by second stone to reach top of pool of water = 3.14 - 1 = 2.14 s

  Time, t =  2.14 m/s

  Acceleration , a = 9.81 m/s²

  Displacement, s = 54 m

  We have equation of motion s= ut + 0.5 at²

 Substituting

   s= ut + 0.5 at²

    54 = u x 2.14 + 0.5 x 9.81 x 2.14²

    u = 14.74 m/s

  Initial velocity of second stone = 14.74 m/s

c) We have equation of motion v = u + at

 For first stone

                  Initial velocity, u =  1.82 m/s

                  Acceleration , a = 9.81 m/s²

                  Time, t = 3.14 s

                  v = 1.82 + 9.81 x 3.14 = 32.62 m/s

 For second stone

                  Initial velocity, u =  14.74 m/s

                  Acceleration , a = 9.81 m/s²

                  Time, t = 2.14 s

                  v = 14.74 + 9.81 x 2.14 = 35.73 m/s

Speed of first stone at the instant the two stones hit the water = 32.62 m/s

Speed of second stone at the instant the two stones hit the water = 35.73 m/s

You might be interested in
Consider two waves X and Y traveling in the same medium. The two carry the same amount of energy per unit time, but X has one-se
RideAnS [48]

Answer:

7 / 1

Explanation:

The ratio of their amplitude = one-seventh and the ratio of their amplitude = the ratio of their wavelength

Ax / Ay = λx / λy  = 1 / 7

λy / λx = 7 / 1

7 0
3 years ago
A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

\mu = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

\omega = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0
3 years ago
WILL MARK AS BRAINLIEST
kumpel [21]
The answer is either C or D.
8 0
3 years ago
Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge
NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is V=\frac{1}{4\pi\epsilon} \frac{q}{d}

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0
3 years ago
A wagon is pulled at a speed of 0.40metets/seconds by a horse exerting an 1,800 Newton's horizontal force. what is the power of
Tatiana [17]

Given:

speed of 0.40meters/seconds

1,800 Newton's horizontal force

Required:

Power of the horse

Solution:

P = F(D/T) where P is power in watts, F is the force, D is the distance and T is time

P = (1,800N) (0.40 meters/seconds)

P = 720 Watts

6 0
3 years ago
Other questions:
  • At a distance D from a very long (essentially infinite)uniform line of charge, the elecric field is 1000 N/C. Forthe field stren
    9·2 answers
  • Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
    7·1 answer
  • Movement of a molecule against its concentration gradient can occur through Select one or more: a. facilitated diffusion b. pass
    10·1 answer
  • How long would it take to walk 10000 miles?
    11·1 answer
  • 60 POINTS ANSWER CORRECTLY
    13·2 answers
  • The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the
    10·1 answer
  • sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o
    5·1 answer
  • An Object with a mass of 40kg is moving at a velocity of 10 m/s. Determine its kinetic energy
    8·1 answer
  • Describe how energy is transformed in the motor
    6·1 answer
  • If mason runs a 5 k race at an average speed of 300 m/min how long will it take him to finish
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!