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xeze [42]
3 years ago
8

During an experiment, iron powder and sulfur powder were heated together to form a black mass. It was observed that a magnet, wh

en brought near the black mass, did not attract the black mass. Which of the following correctly justifies the observation?
A. The black mass is a mixture and no longer retains the properties of iron.
B. The black mass is a mixture and retains the properties of iron.
C.The black mass is a pure substance and no longer retains the properties of iron.
D. The black mass is a pure substance and retains the properties of iron.
Chemistry
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:The correct answer is option(C).

Explanation:

Compound is a substance made up of two or more elements which are chemically joined together.

When the iron and sulfur heated together in the test tube a chemical reaction reaction took place between the iron and sulfur which lead to the formation of iron sulfur compound (here black mass).And this compound will differ in chemical proprieties with respect to its constituting pure element.

When the magnet was brought near to it , it doesn't attracted the black mass towards itself.This is because the 'The black mass is a compound and no longer retains the properties of iron'.

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If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
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