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My name is Ann [436]

3 years ago

13

Name the compound Cd(MnO4).

1 answer:

LekaFEV [45]3 years ago

8 0

I believe that would be Cadmium Permaganate
Hope that helped :)

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What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

ArbitrLikvidat [17]

Data:

m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride ( $Hg_{2} Cl_{2}$ )
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass $Hg_{2} Cl_{2}$ = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

$n = \frac{m}{MM}$

Solving:

$n = \frac{m}{MM}$
$0.714 = \frac{m}{472.09}$
$m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark$

Answer:
By approximation would be letter D) <span>337.2 g</span>

8 0

3 years ago

Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO

elena55 [62]

Answer : The mass of solute in solution is $1.09\times 10^2g$ .

Solution : Given,

Molarity = 0.730 M

Volume of solution = 1.421 L

Molar mass of sodium carbonate = 105.98 g/mole

Formula used for Molarity :

$Molarity=\frac{w}{M\times V}$

where,

w = mass of solute

M = Molar mass of solute

V = volume of solution in liter

Sodium carbonate is solute and water is solvent.

Now put the given values in above formula, we get the mass of solute in solution.

$0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}$

By rearranging the terms, we get

$m=109.247g=1.09\times 10^2g$

Therefore, the mass of solute in solution is $1.09\times 10^2g$ .

4 0

3 years ago

Як визначити амфотерний, луг чи основний елемент в хімії. Коли назви даєш, то пишеш наприклад CuSO4 - амф, купрум сульфат. Чому

Leno4ka [110]

What? Please write in Spanish or English

7 0

3 years ago

ANSWER QUICK TO BE MARKED BRANLIEST 2. Which cell part is responsible for making energy for the cell?

Yakvenalex [24]

Answer:

mitochondrion

4 0

3 years ago

Read 2 more answers

How many particles are present in0.24moles of carbon?

Ray Of Light [21]

Answer:

1.45 x 10²³ particles

Explanation:

Given parameters:

Number of moles of carbon = 0.24moles

Unknown:

Number of particles = ?

Solution:

A mole of a substance contains the Avogadro's number of particles.

The Avogadro's number of particles is 6.02 x 10²³

So;

0.24 moles of carbon will contain 0.24 x 6.02 x 10²³ = 1.45 x 10²³ particles

7 0

2 years ago