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3 years ago

What line in the sky is created by our revolution around the Sun?

Physics

1 answer:

faust18 [17]3 years ago

6 0

Answer:

Ecliptic

Explanation:

You asked for the term that is used to describe Earth going around the sun

The ecliptic is the path the sun, moon, and planets take across the sky as seen from Earth. It best defines the plane of the Earth's orbit around the sun. The imaginary line can best be visualized in the days just before full moon.

Hope it helped

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A small spaceship with a mass of only 2.8 ✕ 103 kg (including an astronaut) is drifting in outer space with negligible gravitati

Luda [366]

Answer:

962.14m/s

Explanation:

Data obtained from the question include:

m (mass) = 2.8x10^3 kg

P (power) = 30 kW = 30 x 1000 = 30000W

V (velocity) =?

t (time) = 1 day

There are 24 hours in a day.

t (time) = 1 day = 24 hours

We need to covert 24 hours to seconds. This is illustrated below:

There are 60 minutes in 1 hour and 60 seconds in 1 minutes.

Therefore, 24hours = 24 x 60 x 60 = 86400 seconds.

t (time) = 1 day = 24 hours = 86400 seconds

Power is related to velocity according to equation:

Power = force x Velocity

P = F x v (1)

Recall Force (F) = Mass (m) x a (acceleration) i.e F = ma

Substituting the value of F into equation 1, we have:

P = F x v

P = ma x v

P = m x a x v (2)

But: acceleration (a) = Velocity(v)/time(t) i.e a = v/t

Substituting the value of a into equation 2, have:

P = m x a x v

P = m x v/t x v

P = (m x v^2)/ t

Now, with this equation

P = (m x v^2)/ t, we can obtain the speed of the spaceship as follow:

P = (m x v^2)/ t

30000 = (2.8x10^3 x v^2) /86400

Cross multiply to express in linear form

2.8x10^3 x v^2 = 30000 x 86400

Divide both side by 2.8x10^3

v^2 = (30000 x 86400)/ 2.8x10^3

v^2 = 925714.2857

Take the square root of both side

v = √(925714.2857)

v = 962.14m/s

Therefore, the speed of the spaceship is 962.14m/s

3 0

3 years ago

Read 2 more answers

In terms of speed and direction in what ways can an object accelerate

kotykmax [81]

An object with less mass

3 0

4 years ago

Read 2 more answers

A 20.0 Ω, 15.0 Ω, and 7.00 Ω resistor are connected in parallel to an emf source. A current of 7.00 A is in the 15.0 Ω resistor.

Lady bird [3.3K]

PART A)

Equivalent resistance in parallel is given as

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$

now we have

$\frac{1}{R} = \frac{1}{20} + \frac{1}{15} + \frac{1}{7}$

$R = 3.85 ohm$

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

$V = iR$

As we know i = 7 A current flows through 15 ohm resistance

$V = (7 A)(15 ohm) = 105 volts$

PART C)

Similarly ohm's law for 20 ohm resistance we can say

$V = iR$

$105 = i(20 ohm)$

$i = 5.25 A$

3 0

4 years ago

Read 2 more answers

Why is the horizontal component of a velocity remains constant in horizontal and inclined projection

lesya692 [45]

Answer:

The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.

8 0

3 years ago

Parallel rays from a distant object are traveling in air and then are incident on the concave end of a glass rod with a radius o

skad [1K]

Answer:

the distance of image from the vertex is 45 cm and the image formed is in the glass.

Explanation:

distance of object, u = - infinity

radius of curvature, R = - 15 cm

refractive index, n = 1.5

Let the distance of image is v.

Use the formula

$-\frac{n1}{u}+\frac{n2}{v}=\frac{n2- n1}{R}\\\\-\frac{1}{\infty }+\frac{1.5}{v}=\frac{1.5-1}{-15}\\\\v=45 cm$

The image is in the glass.

8 0

3 years ago