In order to determine the acceleration of the block, use the following formula:

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

Then, you have:

by solving for a, you obtain:

In this case, you have:
k: spring constant = 100N/m
m: mass of the block = 200g = 0.2kg
x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m
Replace the previous values of the parameters into the expression for a:

Hence, the acceleration of the block is 10 m/s^2
Answer:
KE = 100 J
Explanation: Should be correct
Answer:
2.068 x 10^6 m / s
Explanation:
radius, r = 5.92 x 10^-11 m
mass of electron, m = 9.1 x 10^-31 kg
charge of electron, q = 1.6 x 10^-19 C
As the electron is revolving in a circular path, it experiences a centripetal force which is balanced by the electrostatic force between the electron and the nucleus.
centripetal force = 
Electrostatic force = 
where, k be the Coulombic constant, k = 9 x 10^9 Nm^2 / C^2
So, balancing both the forces we get



v = 2.068 x 10^6 m / s
Thus, the speed of the electron is give by 2.068 x 10^6 m / s.
Answer:
what is the answers? i cant help you without the answers
Explanation:
The prefix your looking for is centi as in centimeter. I got this answer on google.
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