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lukranit [14]
2 years ago
7

A light year is _____.

Physics
2 answers:
Lemur [1.5K]2 years ago
4 0
A light year is a unit of astronomical distance which is equivalent to the distance a light travels in one year( which is nearly 6 trillion miles)

hope this helps :)

777dan777 [17]2 years ago
3 0
Alight year is the distance that ligth travels in a year.

Answer:  C. The distance tat light travels in a year.
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Physics question, any help is appreciated :)
Gekata [30.6K]

Runner 2 sees Runner 1 passing him with a velocity of 17 m/s west.


8 0
2 years ago
Read 2 more answers
Defined the term electromagnetic induction and explain how a generator uses electromagnetic induction​
tatuchka [14]

Is the production of electricity by magnetic field.

There are two types of generator which is <u>D</u><u>.</u><u>C</u><u> </u>generator . And A.C <em>g</em><em>e</em><em>n</em><em>e</em><em>r</em><em>a</em><em>t</em><em>o</em><em>r</em>

A.C gen consist of rectangular coil,brushes and permanent magnet

According to the external force mechanical energy used to rotate coil, due to magnetic flux produced by permanent magnet create induced current, this is to according to flemmings right hand rule of electromagnetic induction the rotating coil will produce current

I hope that will help.

8 0
3 years ago
Proved that<br>V = u+at<br>​
kondaur [170]

Answer:

\sf Proof \ below

Explanation:

We know that acceleration is change in velocity over time.

\sf a=\frac{\triangle v}{t}

\sf a=\frac{v-u}{t}

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

\sf at=v-u

Add u to both sides.

\sf at + u=v

3 0
3 years ago
Read 2 more answers
In a car moving at constant acceleration, you travel 230 m between the instants at which the speedometer reads 40 km/h and 70 km
Goryan [66]
The relationship between the distance covered, initial and final speeds, and time can be expressed through the equation,

First equation,

                    2ad = Vf² - Vi²

Substituting the known values,
                   2(a)(0.230 km) = (70 km/h)² - (40 km/h)²
The value of a from the equation is 7173.92 km/h².

Second equation,
                   d = (Vi)(t) + 0.5at²

Substituting the known values,
                    0.230 km = (40 km/h)(t) + (0.5)(7173.92 km/h²)(t²)

The value of t from the equation is 4.1818 x 10^-3 hours which is also equal to 0.2509 minutes or 15 seconds.

Answer: 15 seconds
7 0
2 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
VLD [36.1K]
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
6 0
3 years ago
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