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Tcecarenko [31]
3 years ago
11

A rock is dropped from rest from a height h above the ground. It falls and hits the ground with a

Physics
1 answer:
Nataliya [291]3 years ago
8 0
Use energy conservation, since no energy is lost it must be constant.

E = 0.5mv² + mgh

At release the velocity v = 0 and the height is h.

E = 0 + mgh

At impact the height h = 0 and the velocity is v.

E = 0.5mv² + 0

Since the energy E is conserved:

0.5mv² = mgh

the mass m cancels and the equation becomes:

0.5v² = gh

h = 0.5v²/g

when g = 9.81 and v = 22:

h = 24,66
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A boy throws a ball up into the air with a speed of 8.2 m/s. The ball has a mass of 0.3 kg. How much gravitational potential ene
diamong [38]
We can use the law of conservation of energy to solve the problem.

The total mechanical energy of the system at any moment of the motion is:
E=U+K = mgh + \frac{1}{2}mv^2
where U is the potential energy and K the kinetic energy.

At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:
E_i = K_i =  \frac{1}{2}mv^2 =  \frac{1}{2}(0.3 kg)(8.2 m/s)^2=10.09 J

When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:
E_f = U_f
But the mechanical energy must be conserved, Ef=Ei, so we have
U_f = K_i
and so, the potential energy at the top of the flight is
U_f = K_i = 10.09 J
7 0
3 years ago
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Which is not a common property of ionic compounds?
Dmitriy789 [7]

Answer:

low melting point

Ionic compounds have high melting and boiling points. This is because a considerable amount of energy is required to break the strong inter-ionic attraction

Explanation:

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3 years ago
Which statements about electric field lines are correct? Check all that apply.
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they cross over one another between charge.

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State the law of refraction
IgorLugansk [536]

Answer:

The law of refraction states that the incident ray, the refracted ray, and the normal to the interface, all lie in the same plane.

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A wheel of mass 4kg is pulled up a plane inclined at 30° to the horizontal by a force of 45N applied to the axle and parallel to
Len [333]

Answer:

v = 10 m/s

Explanation:

Let's assume the wheel does not slip as it accelerates.

Energy theory is more straightforward than kinematics in my opinion.

Work done on the wheel

W = Fd = 45(12) = 540 J

Some is converted to potential energy

PE = mgh = 4(9.8)12sin30 = 235.2 J

As there is no friction mentioned, the remainder is kinetic energy

KE = 540 - 235.2 = 304.8 J

KE = ½mv² + ½Iω²

ω = v/R

KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²

v = √(2KE / (m + I/R²))

v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6

v = 10.07968...

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