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Tcecarenko [31]
3 years ago
11

A rock is dropped from rest from a height h above the ground. It falls and hits the ground with a

Physics
1 answer:
Nataliya [291]3 years ago
8 0
Use energy conservation, since no energy is lost it must be constant.

E = 0.5mv² + mgh

At release the velocity v = 0 and the height is h.

E = 0 + mgh

At impact the height h = 0 and the velocity is v.

E = 0.5mv² + 0

Since the energy E is conserved:

0.5mv² = mgh

the mass m cancels and the equation becomes:

0.5v² = gh

h = 0.5v²/g

when g = 9.81 and v = 22:

h = 24,66
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Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal
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At t =0, the velocity of A is greater than the velocity of B.

We are told in the question that the spacecrafts fly parallel to each other and that for the both  spacecrafts, the velocities are described as follows;

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Learn more: brainly.com/question/24857760

Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?

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reference- socatric q and a

Explanation:

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