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saveliy_v [14]
3 years ago
10

The Bohr effect The Bohr effect describes the effect of solubility on the amount of gas dissolved in blood. describes the effect

of pH on the affinity of hemoglobin for carbon dioxide. describes the effect of pH on the affinity of hemoglobin for oxygen. describes the mechanism of ventilation
Chemistry
2 answers:
Marat540 [252]3 years ago
5 0

Answer:

Option C.

The Bohr effect describes the effect of pH on the affinity of hemoglobin for oxygen.

Explanation:

The hemoglobin is the oxygen carrying part of the blood. However, According to Christian Bohr, the binding affinity for oxygen by the hemoglobin in the blood is greatly affected by the acidity and content of carbon dioxide in the blood. As a matter of fact, they are inversely related. The more acidic the blood is, or the lower the pH of the blood, the lower the amount of oxygen that can become bonded with the hemoglobin in the blood.

9966 [12]3 years ago
3 0

Answer:

describes the effect of pH on the affinity of hemoglobin for oxygen

Explanation:

<em>The Bohr effect </em><em>describes the effect of pH on the affinity of hemoglobin for oxygen.</em>

The Bohr effect refers to the effects created by an increase in the partial pressure of carbon dioxide in the blood on the oxygen binding capacity of the hemoglobin.

The effect was first described by Christian Bohr in 1904 and postulated that the ability of hemoglobin to bind with oxygen decreases with an increase in the partial pressure of carbon dioxide in the blood and vice versa.

<em>As the partial pressure of carbon dioxide increases in the blood, the pH of the blood decreases and this triggers the unloading of oxygen by hemoglobin. T</em><em>his explain how tissues get their required doses of oxygen for their physiological functions. </em>

On the other hand, a decrease in partial pressure of carbon dioxide in the blood leads to an increase in pH and triggers the hemoglobin to bind to more oxygen.

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The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl
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Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of  caffeine extracted is  P =  39.8 \ mg

Explanation:

From the question above  we are told that

    The  K value is  K =  4.6

     The  mass of the caffeine is  m  = 40 mg

      The  volume of water is  V  = 2 mL

      The volume  of caffeine is  v_c =  2 mL

     The number of times the extraction was done is  n =  3

Generally the mass of  caffeine that will be  extracted is  

           P =  m  *  [\frac{V}{K *  v_c + V} ]^3

substituting values  

           P =  40   *  [\frac{2}{4.6 *  2 + 2} ]^3

           P =  39.8 \ mg

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Explanation:

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A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the con
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Mole fraction of Oxygen= (range of moles of oxygen) ÷(general moles)

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The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.

Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.

Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.

The question is incomplete. Please read below to find the missing content.

Assuming that only the listed gases are present, what would the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.

Learn more about the mole fraction here brainly.com/question/14783710

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