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saveliy_v [14]
3 years ago
10

The Bohr effect The Bohr effect describes the effect of solubility on the amount of gas dissolved in blood. describes the effect

of pH on the affinity of hemoglobin for carbon dioxide. describes the effect of pH on the affinity of hemoglobin for oxygen. describes the mechanism of ventilation
Chemistry
2 answers:
Marat540 [252]3 years ago
5 0

Answer:

Option C.

The Bohr effect describes the effect of pH on the affinity of hemoglobin for oxygen.

Explanation:

The hemoglobin is the oxygen carrying part of the blood. However, According to Christian Bohr, the binding affinity for oxygen by the hemoglobin in the blood is greatly affected by the acidity and content of carbon dioxide in the blood. As a matter of fact, they are inversely related. The more acidic the blood is, or the lower the pH of the blood, the lower the amount of oxygen that can become bonded with the hemoglobin in the blood.

9966 [12]3 years ago
3 0

Answer:

describes the effect of pH on the affinity of hemoglobin for oxygen

Explanation:

<em>The Bohr effect </em><em>describes the effect of pH on the affinity of hemoglobin for oxygen.</em>

The Bohr effect refers to the effects created by an increase in the partial pressure of carbon dioxide in the blood on the oxygen binding capacity of the hemoglobin.

The effect was first described by Christian Bohr in 1904 and postulated that the ability of hemoglobin to bind with oxygen decreases with an increase in the partial pressure of carbon dioxide in the blood and vice versa.

<em>As the partial pressure of carbon dioxide increases in the blood, the pH of the blood decreases and this triggers the unloading of oxygen by hemoglobin. T</em><em>his explain how tissues get their required doses of oxygen for their physiological functions. </em>

On the other hand, a decrease in partial pressure of carbon dioxide in the blood leads to an increase in pH and triggers the hemoglobin to bind to more oxygen.

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<h3>How to calculate temperature?</h3>

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Where;

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According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

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