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MAXImum [283]
3 years ago
9

Use the drop-down menus to classify each of these substances,

Chemistry
2 answers:
Lelu [443]3 years ago
6 0

Answer:

Perfume = Ester

Fuel = Alcohol

Anesthetic = Ether

Weak base = Amine

Weak acid = Carboxylic acid

Explanation:

raketka [301]3 years ago
5 0

Answer:

  • Perfume = Ester
  • Fuel = Alcohol
  • Anesthetic = Ether
  • Weak base = Amine
  • Weak acid = Carboxylic acid

Explanation:

Substance abuse is related to misuse of toxic or hazardous substances for example alcohol, and illicit drugs. It leads to the psychoactive substances responsible for substance syndrome.

It is active due to global impairment in cognition, behavioral, and physiological phenomena that are developed after the repeated use of the substances abuse that is related to the strong desire to use the drugs.

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Lorico [155]

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Explanation:

6 0
3 years ago
A substance produces a solution with negative compounds when mixed with water.\
Liono4ka [1.6K]

Answer:

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Explanation:

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3 years ago
What makes gabbro a rock and not a mineral
lozanna [386]
Gabbro is usually made up of such as pyroxene, plagioclase, amphibole and olivine which makes it an intrusive igneous rock. It is not considered as a mineral since it is composed of an aggregate of minerals or non-minerals and does not have one specific chemical composition.
8 0
3 years ago
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Using alcohols as solvents offers the advantage of using RO-ions which are somewhat stronger _than the hydroxide ion. A bases B
bazaltina [42]

Answer:

a -

bases

Explanation:

3 0
3 years ago
How much water, in grams, can be made from
Aleks [24]

Answer:

m_{H_2O}=73.0gH_2O

Explanation:

Hello there!

In this case, since the formation of water from hydrogen and oxygen is:

2H_2+O_2\rightarrow 2H_2O

Whereas we find a 2:2 mole ratio of hydrogen to water. In such a way, by using the Avogadro's number, the aforementioned mole ratio and the molar mass of water (18.02 g/mol), we obtain the following grams of water product:

m_{H_2O}=2.44x10^{24}molec*\frac{1molH_2}{6.022x10^{23}molec}*\frac{2molH_2O}{2molH_2}*\frac{18.02gH_2O}{1molH_2O}\\\\   m_{H_2O}=73.0gH_2O

Regards!

6 0
3 years ago
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