Answer:
the experimental group would be the teachers who recieved the candy
control group would be the teachers who dont get any candy
<em>Explanation:</em>
experimental group is the group that receives the test variable being tested in this case the variable being the candy
and the control group is the group who doesn't receive the variable
purpose of having a control is to rule out other factors which may influence the results of an experiment.
Answer:
Explanation:
To break apart a molecule of H2So4 is much higher than HCl although HCl is an ionic bond it is only bonded to one hydrogen. While H2So4 is bonded to two of them, aswell as its structure being much more complex. The energy to break Ba(h)2 is equal in both.
Decay constant, proportionality between the size of a population of radioactive atoms and the rate at which the population decreases because of radioactive decay.
<h3>What is decay constant value?</h3>
The rate of disintegration is proportional to the number of atoms at any point in time and the constant of proportionality is called the radioactivity decay constant. The radioactive decay constant for Radium B is approximately 4.3 × 10−4 s−1.
<h3>What is decay constant unit?</h3>
Definition. The decay constant (symbol: λ and units: s−1 or a−1) of a radioactive nuclide is its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ. The energies involved in the binding of protons and neutrons by the nuclear forces are ca.
Learn more about decay constant here:
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brainly.com/question/16623902</h3><h3 /><h3>#SPJ4</h3>
Answer:
The molarity of this final solution is 0.167 M
Explanation:
Step 1: Data given
Volume of a 0.100 M HNO3 solution = 50.0 mL
Volume of a 0.200 M HNO3 = 100.0 mL
Step 2: Calculate moles
The final molarity must lie between 0.1M and 0.2M
Moles = molarity * volume
Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol
Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol
total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L
Step 3: Calculate molarity of final solution
Molarity = mol / volume
Molarity 0.025 moles /0.150 L
Molarity = 0.167M
The molarity of this final solution is 0.167 M
