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Genrish500 [490]
3 years ago
9

Which of the following may occur during metamorphism

Physics
1 answer:
Stolb23 [73]3 years ago
6 0
<span>Changes that occur during metamorphism ... The metamorphic rock shale normally becomes following low grade metamorphism.</span>
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the length of time it takes a planet to revolve around the sun is equivalent to witch of the following?
Marina86 [1]
It really depends on how far or close the planet is from the sun

6 0
3 years ago
Read 2 more answers
Help, please<br> and explain
11Alexandr11 [23.1K]
We could tell a force is acting on an object if the object is being pushed, pulled, or moved in any way
5 0
3 years ago
A 1000-kg car moving at 10 m/s brakes to a stop in 5 s. the average braking force is
Marina86 [1]
To calcculate the braking force of the car moving, we use Newton's second law of motion which relates the acceleration and the force of an object moving. The force of an object moving is directly proportional to its acceleration and the proportionality constant is the mass of the object. It is expressed as:

Force = ma

Acceleration is the rate of change of the velocity of a moving object. We calculate acceleration from the velocity and the time given above.

a = (10 m/s) / 5 s = 2 m/s^2

So,
Force = ma
Force = 1000 kg ( 2 m/s^2 )
Force = 2000 kg m/s^2 or 2000 N
4 0
3 years ago
Calculate the wavelength of an orange light wave with a frequency of 5.085 x 10^14 Hz. The speed of light is 3.0 x 10^8 m/s.
Margarita [4]

Answer:

5.9 x 10⁻⁷m

Explanation:

Given parameters:

Frequency = 5.085 x 10¹⁴Hz

Speed of light  = 3.0 x 10⁸m/s

Unknown:

Wavelength of the orange light  = ?

Solution:

The wavelength can be derived using the expression below;

            wavelength  = \frac{v}{f}

v is the speed of light

f is the frequency

            wavelength  = \frac{3 x 10^{8} }{5.085 x 10^{14} }   = 5.9 x 10⁻⁷m

3 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
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