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Genrish500 [490]
3 years ago
9

Which of the following may occur during metamorphism

Physics
1 answer:
Stolb23 [73]3 years ago
6 0
<span>Changes that occur during metamorphism ... The metamorphic rock shale normally becomes following low grade metamorphism.</span>
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EastWind [94]
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3 years ago
Can any one give me examples of cadmium and Zinc together?
gayaneshka [121]
Cadmium zinc telluride, zinc cadmium sulfide
7 0
3 years ago
A pendulum of unknown mass is attached to the ceiling and nearly touches the floor as it completes 6 full cycles in 45 s. At its
lys-0071 [83]

Answer:

a) h = 14 m

b) h = 88 cm

c) f = 0.054 Hz

d) f = 0.13 Hz

Explanation:

a) T = 2π√(L/g)

L = T²g/4π²

L = (45/6)²(9.8) / 4π² = 13.963...

b) ½mv² = mgh

h = v²/2g

h = 4.15²/ (2(9.8)) = 0.87869

c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542

d) f = 6/45 = 0.13333...

6 0
3 years ago
A key falls from a bridge that is 45 m above the water. It falls directly into a model boat, moving with constant velocity, that
guapka [62]

Answer:

4m/s

Explanation:

The motion is in downward direction, and the boat is moving with constant velocity, the position of the boat horizontally is 12m before the key fall.

The height difference "h"= ( y- y°)= 45 m

We can determine the needed time the key requires to reach the water using the expression from Newton's law

h= v(o) + 1/2 at^2

g= acceleration due to gravity= 9.8m/s^2

h= v(o) + 1/2 gt^2 -------------------------eqn*)

V(o)= 0 for the key= initial velocity

h= height that the key falls= 45m

If we substitute the above values into eqn(*) we have

We can make t^2 subject of the formula since v(0)= 0

t^2= h/(1/2 g)

= 45/(1/2× 9.8)

t^2= 45/4.9=9.18

t= √9.18

t=3.03 secs

Since the boat was moving with constant velocity,

Then Velocity= distance/ time

= 12/3.03

Velocity= 4m/s

Hence, the speed of the boat is 4m/s

7 0
3 years ago
A 70.0 kg person climbs stairs, gaining 3.90 meters in height. Find the work done (in J) to accomplish this task.
Veronika [31]

Answer:

Work done, W = 2675.4 J

Given:

mass, m = 70.0 kg

height, H = 3.90 m

Solution:

According to the question, as the person jumps the stairs up, there is an increase in the potential energy of the person which is provided by the work done in climbing the stairs and is given by:

Work done, W = mgH

where

g = acceleration due to gravity = 9.8 m/s^{2}[tex][tex]W = 70.0\times 9.8\times 3.90 = 2675.4 J

6 0
3 years ago
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