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Cerrena [4.2K]
2 years ago
5

The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s.

What is the acceleration of the particle at 3 s?​
Physics
1 answer:
marin [14]2 years ago
6 0

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

v  =  \alpha  +  \beta {t}^{2}

<h3>How to calculate acceleration </h3>

a =  \frac{dv}{dt} \\ v =  \alpha  +  \beta  {t}^{2} \\ \frac{dv}{dt}  = 0 + 2 \beta t \\

if Time is given as 3s

therefore, Acceleration is

a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times  \beta  \times 3 \\ a = 6 \beta

Acceleration is

a = 6 \beta

Read more about velocity:

brainly.com/question/19365526

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