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Cerrena [4.2K]
2 years ago
5

The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s.

What is the acceleration of the particle at 3 s?​
Physics
1 answer:
marin [14]2 years ago
6 0

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

v  =  \alpha  +  \beta {t}^{2}

<h3>How to calculate acceleration </h3>

a =  \frac{dv}{dt} \\ v =  \alpha  +  \beta  {t}^{2} \\ \frac{dv}{dt}  = 0 + 2 \beta t \\

if Time is given as 3s

therefore, Acceleration is

a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times  \beta  \times 3 \\ a = 6 \beta

Acceleration is

a = 6 \beta

Read more about velocity:

brainly.com/question/19365526

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The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00 kHz is 0.750 W/m2. (a) Determine the intensit
sveticcg [70]

Answer:

a)   I = 3.63 W / m² , b)   I = 0.750 W / m²

Explanation:

The intensity of a sound wave is given by the relation

         I = P / A = ½ ρ v (2π f s_{max})²

         I = (½ ρ v 4π² s_{max}²) f²

a) with the initial condition let's call the intensity Io

        cte = (½ ρ v 4π² s_{max}²)

         I₀ = cte s² f₀²

        I₀ = cte 10 6

If frequency is increase f = 2.20 10³ Hz

         I = constant (2.20 10³) 2

         I = cte 4.84 10⁶

let's find the relationship of the two quantities

        I / Io = 4.84

        I = 4.84 Io

        I = 4.84 0.750

        I = 3.63 W / m²

b) in this case the frequency is reduced to f = 0.250 10³ Hz and the displacement s = 4 s or

        I = cte (f s)²

        I = constant (0.250 10³ 4)²

 

        I = cte 1 10⁶

         

the relationship

        I / Io = 1

        I = Io

        I = 0.750 W / m²

6 0
2 years ago
In the Bohr model of the atom, an electron in an orbit has a fixed ____.
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The answer is C. an electron in an orbit has a fixed energy.
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3 years ago
51. Suppose you measure the terminal voltage of a 3.200-V lithium cell having an internal resistance of 5.00Ω by placing a 1.00-
Tanya [424]

Explanation:

Given that,

Terminal voltage = 3.200 V

Internal resistance r= 5.00\ \Omega

(a). We need to calculate the current

Using rule of loop

E-IR-Ir=0

I=\dfrac{E}{R+r}

Where, E = emf

R = resistance

r = internal resistance

Put the value into the formula

I=\dfrac{3.200}{1.00\times10^{3}+5.00}

I=3.184\times10^{-3}\ A

(b). We need to calculate the terminal voltage

Using formula of terminal voltage

V=E-Ir

Where, V = terminal voltage

I = current

r = internal resistance

Put the value into the formula

V=3.200-3.184\times10^{-3}\times5.00

V=3.18\ V

(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf

\dfrac{Terminal\ voltage}{emf}=\dfrac{3.18}{3.200 }

\dfrac{Terminal\ voltage}{emf}= \dfrac{159}{160}

Hence, This is the required solution.

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3 years ago
a 0.4 kg block rests on a desk. the coefficient of static friction is 0.2. You push the side of the block but do not have a spri
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Static friction is greater than Applied force
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3 years ago
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A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha
mylen [45]

Answer:

Rotational kinetic energy = 0.099 J

Translational kinetic energy = 200 J

The moment of inertia of a solid sphere is I = \frac{2}{5}mr^2.

Explanation:

Rotational kinetic energy is given by

\text{RKE} = \frac{1}{2}I\omega^2

where <em>I</em> is the moment of inertia and <em>ω</em> is the angular speed.

For a solid sphere,

I = \frac{2}{5}mr^2

where <em>m</em> is its mass and <em>r</em> is its radius.

From the question,

<em>ω</em> = 49 rad/s

<em>m</em> = 0.15 kg

<em>r</em> = 3.7 cm = 0.037 m

\text{RKE} = \frac{1}{2}\times \frac{2}{5} mr^2\omega^2 = \frac{1}{5} mr^2\omega^2

\text{RKE} = \frac{1}{5} (0.15\ \text{kg})(0.037\ \text{m})^2(49\ \text{rad/s})^2 = 0.099\text{ J}

Translational kinetic energy is given by

\text{TKE} = \frac{1}{2} mv^2

where <em>v</em> is the linear speed.

\text{TKE} = \frac{1}{2} (0.15\ \text{kg})(52\ \text{m/s})^2 = 200\text{ J}

5 0
3 years ago
Read 2 more answers
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