Hello, love! The answer is True, or T, on Edge2020.
Hope this helped!
~ V.
For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

here weight will act at mid point of door so its distance is half of the total distance where force is applied
here we know that

now we will have


so our applied force is 72.5 N
1. One
2. Oohm
Hope this helps
<span> you divide the radius of the </span>wheel<span> by the radius of the </span>axle<span>.</span>
Answer:
I would say A but am not sure