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Hoochie [10]
3 years ago
14

The density of mercury is 13.5 times greater than the density of water. if you were to build a barometer that used water instead

of mercury to record the standard pressure at sea level, what would be the height of that barometer? assume that the mercury barometer is 76 centimeters, or 29.92 inches, long (this is the standard atmospheric pressure at sea level).
Physics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

Height of water column 10.26 m

Explanation:

Given data;

Mercury density is 13.5 times higher than water density.

Mercury barometer 76 cm or 29.92 inches

we know that the mercury column is balanced by the pressure of air  in mercury barometer

we know also standard atmospheric is equivalent to 29.92 inches of mercury

Height of water column must be=  13.5 \times 0.76 cm  = 10.26 meter

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Light of wavelength 400 nm is incident on a single slit of width 15 microns. If a screen is placed 2.5 m from the slit. How far
olganol [36]

Answer:

0.0667 m

Explanation:

λ = wavelength of light = 400 nm = 400 x 10⁻⁹ m

D = screen distance = 2.5 m

d = slit width = 15 x 10⁻⁶ m

n = order = 1

θ = angle = ?

Using the equation

d Sinθ = n λ

(15 x 10⁻⁶) Sinθ = (1) (400 x 10⁻⁹)

Sinθ = 26.67 x 10⁻³

y = position of first minimum

Using the equation for small angles

tanθ = Sinθ = y/D

26.67 x 10⁻³ = y/2.5

y = 0.0667 m

5 0
3 years ago
Which describes the changes in visible light moving from red to violet?
Alexxx [7]
The energy increases
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2 years ago
Nitrogen at 100 kPa and 25oC in a rigid vessel is heated until its pressure is 300 kPa. Calculate (a) the work done and (b) the
nignag [31]

Answer:

A. The work done during the process is W = 0

B. The value of heat transfer during the process Q = 442.83 \frac{KJ}{kg}

Explanation:

Given Data

Initial pressure P_{1} = 100 k pa

Initial temperature T_{1} = 25 degree Celsius = 298 Kelvin

Final pressure P_{2} = 300 k pa

Vessel is rigid so change in volume of the gas is zero. so that initial volume is equal to final volume.

⇒ V_{1} = V_{2} ------------- (1)

Since volume of the gas is constant so pressure of the gas is directly proportional to the temperature of the gas.

⇒ P ∝ T

⇒ \frac{P_{2} }{P_{1}} = \frac{T_{2} }{T_{1}}

⇒ Put all the values in the above formula we get the final temperature

⇒ T_{2} = \frac{300}{100} × 298

⇒ T_{2} = 894 Kelvin

(A). Work done during the process is given by W = P × (V_{2} -V _{1})

From equation (1), V_{1} = V_{2} so work done W = P × 0 = 0

⇒ W = 0

Therefore the work done during the process is zero.

Heat transfer during the process is given by the formula Q = m C_{v} ( T_{2} -T_{1} )

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C_{v} = specific heat at constant volume of nitrogen = 0.743 \frac{KJ}{kg k}

Thus the heat transfer Q = 1 × 0.743 × ( 894- 298 )

⇒ Q = 442.83 \frac{KJ}{kg}

Therefore the value of heat transfer during the process Q = 442.83 \frac{KJ}{kg}

6 0
3 years ago
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nikdorinn [45]

Answer:

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x

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Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.

5 0
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Shkiper50 [21]
<span>Velocities are vectors so we can add them!

Let's let +x be East and -x be West.

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Since our answer is positive that means East so the answer is C.</span>
6 0
3 years ago
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