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Hoochie [10]
3 years ago
14

The density of mercury is 13.5 times greater than the density of water. if you were to build a barometer that used water instead

of mercury to record the standard pressure at sea level, what would be the height of that barometer? assume that the mercury barometer is 76 centimeters, or 29.92 inches, long (this is the standard atmospheric pressure at sea level).
Physics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

Height of water column 10.26 m

Explanation:

Given data;

Mercury density is 13.5 times higher than water density.

Mercury barometer 76 cm or 29.92 inches

we know that the mercury column is balanced by the pressure of air  in mercury barometer

we know also standard atmospheric is equivalent to 29.92 inches of mercury

Height of water column must be=  13.5 \times 0.76 cm  = 10.26 meter

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zmey [24]

Answer:

0.833

Explanation:

Power = energy / time

Power = force × distance / time

Power = force × velocity

P = (850 kg) (9.8 m/s²) (1.00 m/s)

P = 8330 W

P = 8.33 kW

The efficiency of the motor is therefore:

e = 8.33 kW / 10.0 kW

e = 0.833

5 0
3 years ago
Photo shows all! Need help ASAP! Will mark brainlist
Goryan [66]

Answer:

The student is getting different info bc the students probable keeping track of the distance instead of the displacement.

Explanation:

5 0
3 years ago
Student swings a small rubber stopper attached to a string over her head in a horizontal, circular path. The string is 1.50 mete
harkovskaia [24]

Answer:

v = 18.84 m/s

Explanation:

Given that,

The length of the string, r = 1.5 m (it will act as radius)

The rubber stopper makes 120 complete circles every minute.

Since, 1 minute = 60 seconds

It means, its frequency is 2 circles every second.

Let we need to find the average speed of the rubber stopper. It can be calculated as follows :

v=\dfrac{d}{T}

d is distance, d=2\pi r and 1/T = f (frequency)

v=2\pi rf\\\\=2\pi \times 1.5\times 2\\\\=18.84\ m/s

So, the average speed of the rubber stopper is 18.84 m/s.  

4 0
3 years ago
What is the acceleration of the the object during the first 4 seconds?
AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

6 0
3 years ago
If the radius of a blood vessel drops to 84.0% of its original radius because of the buildup of plaque, and the body responds by
erma4kov [3.2K]

To develop this problem it is necessary to apply the equations concerning Bernoulli's law of conservation of flow.

From Bernoulli it is possible to express the change in pressure as

\Delta P = \frac{1}{2}\rho (v_1^2-v_2^2)+ \rho g (h_1h_2)

Where,

v_i =Velocity

\rho = Density

g = Gravitational acceleration

h = Height

From the given values the change of flow is given as

R = r^4P

Therefore between the two states we have to

\frac{R_2}{R_1} = \frac{r_2^4 P_2}{r_1^4 P_1} *100\%

\frac{R_2}{R_1} = \frac{84^4 (110)}{100^4*(100)} *100\%

\frac{R_2}{R_1} = 54.77\%

The flow rate will have changed to 54.77 % of its original value.

4 0
3 years ago
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