Answer:
Kinematics
given,
time (t)=100 s, distance (s)=1 km=1000 m
V
b
=10m/s (relative speed r.p to bus)
Velocity (v)=
time
distance
=
100
1000
V
s
= velocity of scooter
V
b
→ Velocity of bus
V=V
s
−V
b
→As we know
10=V
s
−10
20=V
s
V
s
=20 m/s
Velocity with which scooterist
should chase the bus →20 m/s
Explanation:
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Answer:
You wouldnt fall you would be sucked and you would lose all air supply and you lungs would pop
Explanation:
Answer:
(a) W= 44N
(b)W= 31.65 N
Explanation:
Data
T=44 N : Maximum force that the rope can withstand without breaking
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
(a) We apply the formula (1) at constant speed , then, a=0
W: heaviest fish that can be pulled up vertically
∑F = 0
T-W =0
W = T
W= 44N
(b) We apply the formula (1) , a= 1.26 m/s²
W: heaviest fish that can be pulled up vertically
W= m*g
m= W/g
g= 9.8 m/s² : acceleration due to gravity
∑F = 0
T-W = m*a
T= W+(W/g)*a
44=W*(1+1/9.8)* (1.26 )
44= W* 1.39
W= 44/1.39
W= 31.65 N
