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Elza [17]
3 years ago
7

What are those that you are wearing?

Physics
1 answer:
ExtremeBDS [4]3 years ago
3 0
Some of those checkered polo
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Can someone help please and thank you:)
Ray Of Light [21]

Answer:

The answer is C.

Explanation:

4 0
3 years ago
What statement about energy transfer in a wave is true?
laila [671]

Answer:

Energy moves between the particle of the medium.

Explanation:

8 0
3 years ago
A radio transfers 270 j of energy electrically, 94.5 j is transferred by sound. Work out the efficiency of this radio. Give your
MakcuM [25]

Answer:

35%

Explanation:

Given data

Amount of energy transferred (Input) = 270J

Amount of energy converted to sound (Output)=  94.5J

Efficiency = output/input*100

Efficiency= 94.5/270*100

Efficiency=0.35*100

Efficiency=35%

Hence the efficiency is 35%

6 0
3 years ago
. What type of stress is tension and at what type of plate boundary is it found?
Mrac [35]
The three main types of stress go along with the three types of plate boundaries: compression is common at convergent boundaries, tension at divergent boundaries, and shear at transform boundaries. Hope this helps
7 0
3 years ago
Read 2 more answers
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg
slava [35]

Answer:

Explanation:

mass of first marble m_1=m=0.015\ kg

Initial velocity of the first marble u_1=22.5\ m/s

considering right side as positive

Mass of second marble

m_2=m=0.015\ kg\\u_2=-18\ cm/s

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. v_1=-18\ cm/s

considering v_2 be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

e=\frac{v_2-v_1}{u_1-u_2}

Putting values

1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy =0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J

Final kinetic energy=

0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J

6 0
3 years ago
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