A die is shaped like which solid?
1 answer:
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Answer:
459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution
Explanation:
Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.
The Molarity of a solution is determined by the following expression:
Molarity is expressed in units
In this case:
- Molarity: 1.56 M= 1.56
- Number of moles of calcium chlorine= ?
- Volume= 2.657 liters
Replacing:
Solving:
Number of moles of calcium chlorine= 1.56 M* 2.657 liters
Number of moles of calcium chlorine= 4.14 moles
In other side, you know:
- Ca: 40 g/mole
- Cl: 35.45 g/mole
Then the molar mass of the calcium chloride CaCl₂ is:
CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole
Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?
mass= 459.126 g
<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>
Answer:
A. From 25,0 g of aluminium you will produce 0,927 moles of aluminium chloride
B. From 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride
Explanation:
a. The reaction that you have in this problem is:
3 Cl₂ + 2 Al → 2 AlCl₃
25,0 g of aluminium are:
25,0 ₓ = 0,927 moles
As Al:AlCl₃ ratio is 1, from 25,0 g of aluminium you will produce: <em>0,927 moles of aluminium chloride</em>
b. 30,0 g of chlorine gas are:
30,0 ₓ = 0,423 moles of Cl₂
As Cl₂:AlCl₃ ratio is ³/₂:
0,423 moles of Cl₂ ₓ = <em>0,282 moles of aluminium chloride</em>
Thus, from 30,0 g of chlorine gas you will produce: <em>0,282 moles of aluminium chloride</em>
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I hope it helps!
Answer:
See explanation and images attached
Explanation:
a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.
b) In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.
Mass Molar of 
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
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Mass Molar of = 120 + 62 + 128 = 310 g/mol
Therefore: <span>What is the gram formula mass of Ca3(PO4)2 ?
</span>Answer: 310 grams
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of
Therefore: <span>What is the gram formula mass of Ca3(PO4)2 ?
</span>Answer: 310 grams