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3 years ago

How much energy must be added to a 1-kg piece of granite?

Physics

1 answer:

Gekata [30.6K]3 years ago

4 0

Answer:

Explanation:

Heat energy of a substace can be calculated using

Q = mcθ

where Q = Heat energy

m =mass

c = specific heat capacity

θ =temperature difference

Temperature difference is final temperature - initial temperature.

So we get,

Q = 1 × 600×(100-20)

= 48000 J

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When do vernal equinoxes usually occur? autumnal?

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Spring tides occur twice each lunar month all year long without regard to the season. Neap tides, which also occur twice a month, happen when the sun and moon are at right angles to each other. ... The moon appears full when the Earth is between the moon and the sun

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3 years ago

If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity

MAXImum [283]

The final velocity of object 2 is: 3 m/sec

<h3>What is the conservation of mass?</h3>

According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.

According to conservation of mass,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Given that,

m₁ = 50 kg

m₂ = 75 kg

u₁ = 4 m/s

u₂ = -1 m/s

v₁ = -2 m/s

v₂ = ?

Now, putting the values,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)

or, 125 = -100 + 75 v₂

or, 75 v₂ = 225

or, v₂ = 3 m/sec.

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6 0

1 year ago

Consider a pendulum of length 3. 171 m. The acceleration of gravity is 9. 832 m/s2. A) what is its period at the north pole?answ

ch4aika [34]

The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.

<h3>What is time period of pendulum?</h3>

Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.

The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.

It can be given as,

$T=2\pi \sqrt{\dfrac{L}{g}}$

Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.

A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,

$T=2\pi \sqrt{\dfrac{3.171}{9.832}}\\T=3.57\rm\; s$

Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.

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4 0

2 years ago

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma

ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) $p$ is given by the following equation:

$p=m.V$

Where:

$m=45 kg$ is the mass of the skater

$V$ is the velocity

In this situation the skater has two values of momentum:

Initial momentum: $p_{1}=m.V_{1}$

Final momentum: $p_{2}=m.V_{2}$

Where:

$V_{1}=3 m/s$

$V_{1}=5 m/s$

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

$p=p_{2}-p_{1}=m.V_{2}-m.V_{1}$