Question

The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Consider an RLC circuit with Epeak = 90 V, R = 28.9 capital omega, L = 1.31 H, and C = 2.86 µ F. Find the amplitude of the voltage across the inductor at resonance. V

Answer 1

Answer:

VL=2107.6v

Explanation:

at resonance xc=xL

1/wc = wL

z=R

because sqr(R^2+(xL-xc))

^

(xL=xc)

V/R=I

90/28.9=3.1142A

w=1/sqr(1.31×(2.86×10^-6))=516.63

xL= wL

xL= 516.63×1.31=676.785

VL=3.1142×676.785

VL=2107.6v