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Semmy [17]
3 years ago
10

The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Con

sider an RLC circuit with Epeak = 90 V, R = 28.9 capital omega, L = 1.31 H, and C = 2.86 µ F. Find the amplitude of the voltage across the inductor at resonance. V
Physics
1 answer:
Degger [83]3 years ago
4 0

Answer:

VL=2107.6v

Explanation:

at resonance xc=xL

1/wc = wL

z=R

because sqr(R^2+(xL-xc))

^

(xL=xc)

V/R=I

90/28.9=3.1142A

w=1/sqr(1.31×(2.86×10^-6))=516.63

xL= wL

xL= 516.63×1.31=676.785

VL=3.1142×676.785

VL=2107.6v

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A cue stick hits a cue ball with an average force of 22 N for a duration of 0.029 s. If the mass of the ball is 0.15 kg, how fas
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Answer:

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Explanation:

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8 0
3 years ago
Read 2 more answers
12. The diameter of a circle is 2.42m. Calculate its<br>area in proper significant figure​
Sever21 [200]

Answer:

A = 4.6 [m²]

Explanation:

The area of a circle can be calculated by means of the following equation.

A=\frac{\pi }{4} *D^{2}

where:

A = area [m²]

D = diameter = 2.42 [m]

Now replacing:

A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ]

7 0
3 years ago
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