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UkoKoshka [18]
3 years ago
10

A solution contains 1 LaTeX: \times\:×10−4 M OH– ions. Calculate the solution pH value, and determine if the solution is acidic,

basic, or neutral. Helpful math formulas: LaTeX: pH=-\log\left[H_3O^+\right]p H = − log ⁡ [ H 3 O + ] LaTeX: pOH=-\log\left[OH^-\right]p O H = − log ⁡ [ O H − ] LaTeX: pH+pOH=14.00p H + p O H = 14.00 LaTeX: \left[H_3O^+\right]\left[OH^-\right]=1.0\times10^{-14}
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0

<u>Answer:</u> The pH value of the solution is 10 and the solution is basic in nature.

<u>Explanation:</u>

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=1\times 10^{-4}M

Putting values in above equation, we get:

pOH=-\log(1\times 10^{-4})\\\\pOH=4

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4=10

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

  • The pH range of acidic solution is 0 to 6.9
  • The pH range of basic solution is 7.1 to 14
  • The pH of neutral solution is 7.

As, the pH of the solution is 10 and is lying in the range of basic solution, so the solution is basic in nature.

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Explanation:

The given data is as follows.

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Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

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Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

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Hence, the total pressure will be as follows.

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Composition of CCl_{4} is 0.8405 .

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To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

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<em>V is volume in liters</em>

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<em />

Replacing:

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<h3>1.18x10⁸L of SO₂ and:</h3>

<em>9.36x10⁶ moles H₂S</em> * 0.082atmL/molK * 295.15K / 0.961atm =

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Answer:

See explanation

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