3 years ago

Please help question is attached

1 answer:

4 0

Top R is physical. Top L is chem. Bottom L is physical. Bottom R is chem.

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IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = $x_{A}\times P_{A}^{0}$

vapour pressure of a component (B) in solution = $x_{B}\times P_{B}^{0}$

Where $x_{A},x_{B}$ are mole fraction of component A and B in solution respectively

$P_{A}^{0},P_{B}^{0}$ are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = $0.340\times 745 torr$

= 253 torr

7 0

3 years ago

adoni [48]

Answer:

Explanation:

they watched there mother

6 0

3 years ago

shutvik [7]

Its an example of inference.

4 0

4 years ago

ss7ja [257]

Answer:

d. Because those chemicals are easily made when CO2 reacts with water, forming H2CO3 (via carbonic anhydrase

3 0

3 years ago

melisa1 [442]

Answer:

I HOPE THE ABOVE INFORMATION WILL HELP YOU A LOT.

HAVE A NICE DAY.

3 0

3 years ago