Qc < Kc, the reaction proceeds from left to right to reach equilibrium
<h3>Further explanation
</h3>
Given
K = 50.2 at 445°C
[H2] = [I2] = [HI] = 1.75 × 10⁻³ M At 445ºC
Reaction
H2(g) + I2(g) ⇔2HI(g)
Required
Qc
Solution
Qc for the reaction
![\tt Qc=\dfrac{[HI]^2}{[I_2][H_2]}\\\\Qc=\dfrac{(1.75.10^{-3})^2}{1.75.10^{-3}\times 1.75\.10^{-3}}=1](https://tex.z-dn.net/?f=%5Ctt%20Qc%3D%5Cdfrac%7B%5BHI%5D%5E2%7D%7B%5BI_2%5D%5BH_2%5D%7D%5C%5C%5C%5CQc%3D%5Cdfrac%7B%281.75.10%5E%7B-3%7D%29%5E2%7D%7B1.75.10%5E%7B-3%7D%5Ctimes%201.75%5C.10%5E%7B-3%7D%7D%3D1)
Qc < Kc ⇒ reaction from left(reactants) to right (products) (the reaction will shift on the right) until it reaches equilibrium (Qc = Kc)
Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
<h2>Answer : Option A) true</h2><h3>Explanation : </h3>
CO which is carbon monoxide is a primary pollutant for air pollution. As it contributes to the major proportion in the air pollutants amongst others. It has 48% percent of pollutants in comparison to other pollutants of air. The source of carbon monoxide is mainly from incomplete combustion of fuel mostly from the older cars.
The rise in atmospheric CO results in fatigue, drowsiness and my also sometimes lead to death of the person exposed to it.
Answer:
35 amu
Explanation:
In an atom, only masses of protons and neutrons are relevant. electrons are so small in size that their masses are negligible.
The mass of 1 proton/neutron is 1amu.
An isotope is defined as an element that has the same number of protons as the common element but different number of neutrons. In this case, a beryllium atom has a molar weight of 10 amu. Thus, there are 4 protons and 6 neutrons. The nuclear symbol of Be-10 is 4 Be10
