Atomic mass of F: 19.0 g/mol
Atomic mass of S: 32.1 g/mol
1.18 g F = [1.18 g / 19.0 g / mol] = 0.062 mol F
1 g S = 1 g/ 32.1 g/mol = 0.031 mol S
Divide by 0.031
0.062 mol F / 0.031 = 2 mol F
0.031 mol S / 0.031 = 1 mol S
SF2 Then X = 2
Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g
36 gF / 32.1 g S = 1.18 g F / g S
Answer:
3.91 L
Explanation:
Using the ideal gas law equation as follows:
PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
Based on the information given in this question,
P = 5.23 atm
V= ?
n = 0.831 mol
T = 27°C = 27 + 273 = 300K
Using PV = nRT
V = nRT/P
V = (0.831 × 0.0821 × 300) ÷ 5.23
V = 20.47 ÷ 5.23
V = 3.91 L
Answer:
The answer is A
Explanation:
That is the only answer that even remotely resembles an ultrasound hope this answered your question.
Hey there!
A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.
If 50%, or half, of the element remains after 4000 years, that means the half life must be 4000 years.
Hope this helps!
Answer:
Explanation:
48.16%
Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.
Hope This Helps :)
