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nordsb [41]
3 years ago
13

A tool use to quickly develop quality database design by reusing commonly available data models which are applicable to the ente

rprises requirements and customizing the details for the application at hand
a. integrated data model
b. integrated management information system
c. business process re-engineering
d. supply chain management
Physics
1 answer:
Trava [24]3 years ago
5 0
U can be helped at flash cards
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A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f
AleksAgata [21]

Answer:

Part a)

When rotated about the mid point

\tau = 0.021Nm

Part b)

When rotated about its one end

\tau = 0.042 Nm

Explanation:

As we know that the angular acceleration of the rod is rate of change in angular speed

so we will have

\alpha = \frac{\Delta \omega}{\Delta t}

\alpha = \frac{2.4 - 0}{3.6}

\alpha = 0.67 rad/s^2

Part a)

When rotated about the mid point

I = 2mr^2

I = 2(0.48)(0.18)^2

I = 0.0311 kg m^2

now torque is given as

\tau = 0.0311 (0.67)

\tau = 0.021Nm

Part b)

When rotated about its one end

I = m(2r)^2

I = (0.48)(0.36)^2

I = 0.0622 kg m^2

now torque is given as

\tau = (0.0622)(0.67)

\tau = 0.042 Nm

3 0
3 years ago
Which is a characteritic of a physical change?
blagie [28]
Some thing that is done physically like with a persons hands and such
4 0
3 years ago
How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?
gtnhenbr [62]

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

7 0
3 years ago
If the initial upward speed of the ball in Activity 7 C.2 is 10m/s, and the ball is releasedat a height of 1.5 m above the oor,
Ulleksa [173]

Answer:

6.5 m above the floor and 5 m above Christine's hand when it reaches the maximum height.

Explanation:

Let g = 10 m/s2 be the gravitational deceleration that affects the ball vertical motion so it comes to the maximum height at 0 speed. We can use the following equation of motion to find out the distance traveled by the ball from where it's thrown:

v^2 - v_0^2 = 2g\Delta s

where v = 0 m/s is the final velocity of the ball when it reaches maximum level, v_0 = 10m/s is the initial velocity of the ball when it starts, g = -10 m/s2 is the deceleration, and \Delta s is the distance traveled, which we care looking for:

0^2 - 10^2 = -2*(-10)\Delta s

\Delta s = 100 / (2 * 10) = 5 m

So the ball is 5 m above Christine' hands when it reaches maximum height, and since the hand is 1.5 m above the floor, the ball is 5 + 1.5 = 6.5 m above the floor when it reaches maximum height.

5 0
3 years ago
Read 2 more answers
What is the most abundant element in the universe?<br> A. helium<br> B. hydrogen<br> C. carbon
Naya [18.7K]
The answer is Carbon
3 0
3 years ago
Read 2 more answers
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