A because if you multiple it, you will be moving the decimal one time
In chemistry, there is a common note that says, "Like dissolves like".
This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances.
Polarity of the substance depends primarily on the type of bond and the difference in electronegativity.
Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical.
A because the outcome of this reaction exists a radical formed by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol serves as the ring substituent in this condition.
<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
- The methyl group exists moved to cytosine in the first step, and it exists then hydroxylated in the second stage.
- Thus, a transferase and an oxidoreductase exist as the two groups of enzymes needed.
<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
- Hydrogen bonding because the glucose's OH would create an H-bond with any disclosed polar side chains on a protein surface.
<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH?</h3>
- Only positively charged proteins can attach to a cation-exchange column, and this can only occur when the pH exists lower than the pI.
- Proteins A and B would both be positively charged at pH 7.0.
To learn more about hydroxyquinoline refer to:
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<em>Answer </em>
<em>no</em><em>. </em><em>of</em><em> </em><em>moles</em><em> </em><em>=</em>
<em>
</em>
so, <em>mass</em><em> </em><em>(</em><em>g</em><em>)</em><em>=</em><em> </em><em>no</em><em>. </em><em>of</em><em> </em><em>mol</em><em>es</em><em> </em><em>×</em><em> </em><em>molecular </em><em>wight </em>
Explanation:
Li molecular wight equal to 6.941
mass (g)=3.29×104 <em>mol</em><em> </em><em>×</em><em>6</em><em>.</em><em>9</em><em>4</em><em>1</em><em> </em><em>=</em><em>2</em><em>3</em><em>7</em><em>4</em><em>.</em><em>9</em><em>3</em><em>g</em><em> </em><em>of</em><em> </em><em>lithium </em>