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zimovet [89]
3 years ago
14

An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a rate of 1.5 ft3/s th

rough a constant-diameter pipe. The free surface of the pool is 80 ft above that of the lake. Determine the mechanical power used to overcome frictional effects in piping.
Engineering
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

mechanical power used to overcome frictional effects in piping is 2.37 hp

Explanation:

given data

efficient pump = 80%

power input = 20 hp

rate = 1.5 ft³/s

free surface = 80 ft

solution

we use mechanical pumping power delivered to water is

{W_{u}}= \eta  {W_{pump}}  .............1

put here value

{W_{u}}  = (0.80)(20)

{W_{u}} = 16 hp

and

now we get change in the total mechanical energy of water is equal to the change in its potential energy

\Delta{E_{mech}} = {m} \Delta pe   ..............2

\Delta {E_{mech}} = {m} g \Delta z  

and that can be express as

\Delta {E_{mech}} = \rho Q g \Delta z     ..................3

so

\Delta {E_{mech}} = (62.4lbm/ft^3)(1.5ft^3/s)(32.2ft/s^2)(80ft)[\frac{1lbf}{32.2lbm\cdot ft/s^2}][\frac{1hp}{550lbf \cdot ft/s}]      ......4

solve it we get

\Delta {E_{mech}} = 13.614 hp

so here

due to frictional effects, mechanical power lost in piping

we get here

{W_{frict}} = {W_{u}}-\Delta {E_{mech}}  

put here value

{W_{frict}} = 16 -13.614

{W_{frict}} = 2.37  hp

so mechanical power used to overcome frictional effects in piping is 2.37 hp

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Answer: Your question has some missing figures so kindly plug in the values into the solution provided to get the exact amount of money saved

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Explanation:

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5 0
3 years ago
A square-thread power screw has a major diameter of 32 mm and a pitch of 4 mm with single threads, and it is used to raise a loa
Valentin [98]

Answer:

54mm.

Explanation:

So, we are given the following data or parameters or information that is going to assist in solving this type of question efficiently;

=> "A square-thread power screw has a major diameter of 32 mm"

=> "a pitch of 4 mm with single threads"

=> " and it is used to raise a load putting a force of 6.5 kN on the screw."

=> The coefficient of friction for both the collar and screw is .08."

=> "If the torque from the motored used to raise the load is limited to 26 N×M."

Step one: determine the lead angle. The lead angle can be calculated by using the formula below;

Lead angle = Tan^- (bg × T/ Jh × π ).

=> Jh = J - T/ 2. = 32 - 4/2. = 30mm.

Lead angle = Tan^- { 1 × 4/ π × 30} = 2.43°.

Step two: determine the Torque required to against thread friction.

Starting from; phi = tan^-1 ( 0.08) = 4.57°.

Torque required to against thread friction = W × Jh/2 × tan (lead angle + phi).

Torque required to against thread friction =( 6500 × 30/2) × tan ( 2.43° + 4.57°). = 11971.49Nmm.

Step three: determine the Torque required to against collar friction.

=> 2600 - 11971.49Nmm = 14028.51Nmm.

Step four = determine the mean collar friction.

Mean collar friction = 14028.51Nmm/0.08 × 6500 = 27mm

The mean collar diameter = 27 × 2 = 54mm.

5 0
3 years ago
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murzikaleks [220]

Answer:

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Explanation:

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7 0
3 years ago
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Lesechka [4]

Answer:

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option A. actuator

is correct

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