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Maru [420]
4 years ago
8

Standard Reduction Potentials in Aqueous Solution at 25 °C

Chemistry
1 answer:
7nadin3 [17]4 years ago
6 0

Answer:

Hope this helps:)

Explanation:

The values for the table entries are reduction potentials, so lithium at the top of the list has the most negative number, indicating that it is the strongest reducing agent. The strongest oxidizing agent is fluorine with the largest positive number for standard electrode potential.

Elemental fluorine, for example, is the strongest common oxidizing agent.

Lithium metal is therefore the strongest reductant (most easily oxidized) of the alkali metals in aqueous solution. The standard reduction potentials can be interpreted as a ranking of substances according to their oxidizing and reducing power

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Calculate the temperature required to make a 75.8 ml ballon initially at 57.9c change its value to 50.8ml
nika2105 [10]

Answer:

T₂ = 221.8 K

Explanation:

Given data:

Initial temperature = 57.9°C ( 57.9+273 =330.9 k)

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V₁ /T₁= V₂/T₂

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3 years ago
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Neporo4naja [7]

Answer:

The answer to your question is below

Explanation:

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Atomic number = 24.31 g

-Use the Avogadro's number to find the number of atoms

                          24.31g ------------------- 6.023 x 10²³ atoms

                           0.143 g -----------------  x

                           x = (0.143 x 6.023 x 10²³) / 24.31

                           x = 8.613 x 10²² / 24.31

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2) 0.101 kg of Ti into atoms

-Look for the atomic number of Titanium in the Periodic table

Atomic number = 47.87 g

-Use the Avogadro's number to find the number of atoms

                      47.87 g --------------------- 6.023 x 10²³

                      101 g    ----------------------  x

                       x = (101 x 6.023 x 10²³) / 47.87

                       x = 6.08x 10²⁵ / 47.87

                      x = 1.27 x 10²⁴ atoms                            

3 0
3 years ago
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