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Maru [420]
4 years ago
8

Standard Reduction Potentials in Aqueous Solution at 25 °C

Chemistry
1 answer:
7nadin3 [17]4 years ago
6 0

Answer:

Hope this helps:)

Explanation:

The values for the table entries are reduction potentials, so lithium at the top of the list has the most negative number, indicating that it is the strongest reducing agent. The strongest oxidizing agent is fluorine with the largest positive number for standard electrode potential.

Elemental fluorine, for example, is the strongest common oxidizing agent.

Lithium metal is therefore the strongest reductant (most easily oxidized) of the alkali metals in aqueous solution. The standard reduction potentials can be interpreted as a ranking of substances according to their oxidizing and reducing power

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What mass of octane must be burned in order to liberate 5270 kj of heat? δhcomb = -5471 kj/mol?
katrin2010 [14]
As,
                           5471 kJ heat is given by  =  1 mole of Octane
Then,
                    5310 kJ heat will be given by  = X moles of Octane

Solving for X,
                                  X  =  (5310 kJ × 1 mol) ÷ 5471 kJ

                                  X  =  0.970 moles of Ocatne

So, 0.970 moles of Octane will liberate 5310 kJ energy. Now changing moles to mass,
As,
                                  Moles  =  mass / M.mass
Or,
                                  Mass  =  Moles × M.mass
Putting values,
                                  Mass  =  0.970 mol × 114.23 g/mol

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Base A dissociates 25% in water. Base B dissociates 50%. Base C dissociates
torisob [31]

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so this is right answer

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