Answer:
Explanation:
The resultant velocity of the motorboat due to the current perpendicular to the motion of the boat can be calculated by drawing a triangle to represent this motion. The velocity of the motorboat is the base whereas the velocity of the river is the perpendicular of the triangle (picture attached).
The angle is (perpendicular/base);
(5/20)= 14.0;
The triangle can be enlarged such that the perpendicular now represents the width of the river and the perpendicular represents the distance between the dock and landing place.
The distance between dock and landing place is:
a) base*Tan(∅) = 2*Tan(14) = 0.5km
b Time = 2/20= 0.1 hours. This is because the horizontal component of the motion due to velocity of motor boat will be considered for horizontal distance of 2 km.
Answer:
The child represented by a star on the outside path.
Explanation:
1. The formula for momentum is:
p = mv
p =75(18) = 1350 kg-m/s
2. We equate the momentum of the two objects
0.25 v = 0.05 (500)
v = 100 m/s
3. We use the formula for impulse:
Δmv = FΔt
55(20) = F(0.5)
F = 2200 N
Answer:
Explanation:
Electrical potential energy will be converted into kinetic energy .
Electrical potential energy when distance was 15 m .
E₁ = 9 x 10⁹ x - q² /d where q is magnitude of charge on electron or positron
E₁ = 9 x 10⁹ x - ( 1.6 x 10⁻¹⁹ )² /15
= - 1.536 x 10⁻²⁹ J .
Electrical potential energy when distance was 2 m .
E₁ =9 x 10⁹ x - q² /d where q is magnitude of charge on electron or positron
E₁ = 9 x 10⁹ x - ( 1.6 x 10⁻¹⁹ )² /2
= -11.52 x 10⁻²⁹ J .
Decrease in energy = (11.52 - 1.536 ) x 10⁻²⁹
= 9.984 x 10⁻²⁹ J .
This energy will be converted into kinetic energy and they will be distributed equally in each .
Energy of each = 9.984 x 10⁻²⁹ /2
= 4.992 x 10⁻²⁹ J .
1/2 m v² = 4.992 x 10⁻²⁹ , m is mass of electron
.5 x 9.1 x 10⁻³¹ v² = 4.992 x 10⁻²⁹
v² = 109.71
v = 10.47 m/s .