Answer:
In the line marked *, the strategy that was used was renaming a fraction
The expression de-c fills in the orange box.
Explanation:
just did those questions 2020egen
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(I’m not sure if that’s right a picture below may help with the answer too)
Answer:
At the point when the quantity of bit strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just part strings to processors and not client level strings to processors. At the point when the quantity of part strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used all the while. Be that as it may, when a part string obstructs inside the portion (because of a page flaw or while summoning framework calls), the comparing processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, in this way expanding the use of the multiprocessor system.When the quantity of part strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just bit strings to processors and not client level strings to processors. At the point when the quantity of bit strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used at the same time. Be that as it may, when a part string hinders inside the piece (because of a page flaw or while summoning framework calls), the relating processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, along these lines expanding the usage of the multiprocessor framework.
Answer:
The electrical power is 96.5 W/m^2
Explanation:
The energy balance is:
Ein-Eout=0
if:
Gsky=oTsky^4
Eb=oTs^4
qc=h(Ts-Tα)
if Gl≈El(l,5800)
lt= 2*5800=11600 um-K, at this value, F=0.941
The hemispherical emissivity is equal to:
lt=2*333=666 K, at this value, F=0
The hemispherical absorptivity is equal to:
Answer:
A) ν = 0.292
B) ν = 0.381
Explanation:
Poisson's ratio = - (Strain in the direction of the load)/(strain in the direction at right angle to the load)
In axial tension, the direction of the load is in the length's direction and the direction at right angle to the load is the side length
Strain = change in length/original length = (Δy)/y or (Δx)/x or (ΔL/L)
A) Strain in the direction of the load = (2.49946 - 2.5)/2.5 = - 0.000216
Strain in the direction at right angle to the load = (7.20532 - 7.2)/7.2 = 0.0007389
Poisson's ratio = - (-0.000216)/(0.0007389) = 0.292
B) Strain in the direction of the load = (2.09929 - 2.1)/2.1 = - 0.0003381
Strain in the direction at right angle to the load = (5.30470 - 5.3)/5.3 = 0.0008868
Poisson's ratio = - (-0.0003381)/(0.0008868) = 0.381
