The answer would be <span>72 kg'm/s b</span>ecuase the wall is pushing off 9 becuase it took 5 and bounced back off 4 so
9 times 8= 72 kg m/s
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
"Estuaries" <span> is most likely to contain brackish water
Hope this helps!</span>
From the calculation, the force constant is 192 N. Also, friction would decrease the extension.
<h3>What is the force constant?</h3>
We know that the force constant can be obtained by the use of the relation;
F = Ke
F = applied force
K = force constant
e = extension
We know from Hooks law that the force applied is directly proportional to the extension.
We can write;
F = mgcosθ
F = 43 Kg * 9.8 m/s^2 * sin31°
F = 217 N
K = 217 N/1.13 m
K = 192 N/m
If there is friction between the incline and the crate, it will stretch less because some work will be lost due to friction causing only some fraction of the elastic potential energy to be converted to kinetic energy.
Learn more about Hooke's law:brainly.com/question/14140269
#SPJ1