Answer:
0.037 A
Explanation:
Magnetic field = B = 1.00 e-4 T
Length = L = 0.380 m
Number of turns = 810
B = μ₀ N I / L
⇒ Current = I = B L / μ₀ N = ( 1 e-4) ( 0.380) / (4π × 10⁻⁷)(810)
= 0.037 A = 37.3 mA
The impulse experienced by the object is 3 N s.
<u>Explanation:</u>
Impulse is also termed as change in the momentum of the object. So, it is directly proportional to the force acting on the object and the time for which the force is acting on that object.
Thus, impulse experienced by an object is the product of force acting on the object for a given time period. So, it is the sudden influence of force on the given volume.
As the force is given as 30 N and the duration or the time is given as 0.1 seconds. Then, the impulse will be product of force with duration.
Impulse = Force × ΔTime = Force × Duration
Impulse = 30 × 0.1 = 3 N s.
Thus, the impulse experienced by the object is 3 N s.
A material that does not conduct electricity is known as an insulator
The <em>mass</em> of an object is a measure of how much stuff it's made of. So it's
a property of the object, like the object's length or color. It doesn't depend on
where the object is located right now, or on what else is around it..
The <em>weight</em> of an object is the measure of the gravitational force between it
and something else. The strength of the force depends on the size of both
masses, and also on how far apart they are. So the weight does depend on
where the object is located right now, and on what else is around it.
I think that sums it up fairly well.
Answer:
<u><em></em></u>
- <u><em>1,500 kg.m/s</em></u>
Explanation:
First, arrange the information in a table:
Object Mass (kg) Velocity (m/s)
A 200 15
B 150 - 10
After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.
According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.
<u>Momentum before the collision, P₁</u>:
![P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}](https://tex.z-dn.net/?f=P_1%3Dm_%7BA%2C1%7D%5Ctimes%20v_%7BA%2C1%7D%2Bm_%7BB%2C1%7D%5Ctimes%20v_%7BB%2C1%7D)
![P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\ P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s](https://tex.z-dn.net/?f=P_1%3D200kg%5Ctimes%2015m%2Fs%2B150kg%5Ctimes%20%28-10m%2Fs%29%5C%5C%5C%5C%20%20P_1%3D3000kg.m%2Fs-1500kg.m%2Fs%3D1500kg.m%2Fs)
<u>Momentum after the collision</u>:
- As stated, it es equal to the momentum before the collision: 1,500 kg . m/s