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3 years ago

Do you think that solids can undergo convection? EXPLAIN!

Physics

2 answers:

sukhopar [10]3 years ago

8 0

No. Solids can't undergo convection,

Explanation:

Convection is heat removal by movement hot matter as exposed to cold matter bure to density differences in the expression of the gravity field. or heat transfer within moving currents.Convection works because hotter quicker moving molecules have a lower frequency and consequently rise to the surface. In a solid the molecules can't move corresponding to each other they can only vibrate

Katarina [22]3 years ago

4 0

<span>No. Solids can't undergo convection, the reason is that convection works because moving molecules which are hotter and faster have a lower density and therefore rise to the surface. With a solid now, the molecules don't move they can only vibrate.

Therefore solids conduct.</span>

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Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

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$\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}$ .

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$\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}$ .

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