Answer:
Mass of KNO3= 10g
Molar mass of KNO3 = 101.1032g/mol
Volume = 250ml = 0.25L
No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3
no of mole of KNO3 = 10/101.1032
No of mole of KNO3 = 0.09891
molarity of KNO3 = no of mole of KNO3/Vol (L)
Molarity = 0.09891/0.25 = 0.3956M
Molarity of KNO3 = 0.3956M
Answer:
554.86kj
Explanation: Since 1 mole of CaC2=15.14kj yield 1mole of C2H2
The enthalpy change of H2O is 2*285=570
570+-15.14=554.86kj
Hence Hp is 554.86kj
He=Hp
The osmotic pressure of the glucose solution is 21.49 atm.
From the question given above, the following data were obtained:
- Molarity (M) = 0.85 M
- Temperature (T) = 35 °C = 35 + 273 = 308 K
- Van't Hoff's factor (i) = 1 (non-electrolyte)
- Gas constant (R) = 0.0821 atm.L/Kmol
- Osmotic pressure (π) =?
π = iMRT
π = 1 × 0.85 × 0.0821 × 308
π = 21.49 atm
Therefore, the osmotic pressure is 21.49 atm
Learn more about osmotic pressure: brainly.com/question/19533851
Explanation:
The relation between 
is given by :
Where :
= Ionic prodcut of water
The value of the first ionization constant of sodium sulfite = 
The value of 
:
The value of the second ionization constant of sodium sulfite = 
The value of 
:
