Answer:
The bond order for C2 molecule is 2.
Explanation:
Bond order can be defined as the half of the difference between the number of electrons in the bonding orbital and the number of electrons in the antibonding orbitals. It can be represented mathematically by; .
Bond order,n= [number of electrons in the bonding molecular orbitals(BMO) - the number or electrons in the anti-bonding molecular orbitals(AMO) ] / 2.
The electronic configuration of the C2 molecule is given below;
C2 = (1sσ)^2 (1s^*σ)^2 (2sσ)^2 (2s^*σ)^2 (2pπ)^4.
The ones with the (*) are known as the Anti-bonding molecular orbitals while the ones without (*) are known as the bonding molecular orbitals. Hence, we have 8 Electrons from the bonding molecular orbitals and 4 Electrons from the anti-bonding molecular orbitals.
So, from the formula given above, the bond order of C2 molecule is;
===> 8-4/2= 4/2.
===> 2.
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Higher value- mass number
Lower value- atomic number/ number of proton
Answer is: volume of the sample is 36,2 mL.
V₁(sample) = 17 mL.
T₁(sample) = −112°C = -112 + 273,15 = 161,15 K.
T₂(sample) = 70°C = 70 + 273,15 = 343,15 K.
V₂(sample) = ?
Charles' Law: V₁/T₁ = V₂/T₂.
17 mL/161,15 K = V₂/343,15 K.
161,15 K · V₂ = 17 mL · 343,15 K
V₂ = 5833,55 K·mL ÷ 161,15 K
V₂ = 36,2 mL.
