All the stars, spheres and galaxies that can be perceived nowadays
make up just 5 percent of the universe.
The former 95 percent is prepared of stuff stargazers can't see, notice or even
understand. These secretive substances are called dark energy and
dark matter. Experts determine their presence grounded on their gravitational
influence on what little bits of the universe can be perceived.
Answer:
A. increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
Explanation:
Strong Nuclear force: it is the short range force and strongest fundamental force in all type of forces.
Electromagnetism: this is the force due to magnetic and electric behavior of the particles. It is moderate type of force and its range is more than Nuclear force.
Weak Nuclear Force: This force is also short range force which act between the nucleoside. But this force is also moderate type of force
Gravitational force: this force is between two point masses and least order of force. also the range of this force is upto infinite.
so the correct order of this fundamental force is
<em>strong nuclear, electromagnetism, weak nuclear, gravitational</em>
Answer:
If transpiration didn't take place water would still be able to enter the roots of a plant
Explanation:
transpiration is the process of water leaving from living organisms to the atmosphere, therefore, if transpiration didn't occur the water would not transpire to the atmosphere and would remain in the root but water absorption would not change because it is a biological need for the living organism as such
Answer:
The work done on the Frisbee is 1.36 J.
Explanation:
Given that,
Mass of Frisbee, m = 115 g = 0.115 kg
Initial speed of Frisbee, u = 12 m/s at a point 1 m above the ground
Final speed of Frisbee , v = 10.9674 m/s when it has reached a height of 2.00 m. Let W is the work done on the Frisbee by its weight. According to work energy theorem, the work done is equal to the change in its kinetic energy. So,

So, the work done on the Frisbee is 1.36 J. Hence, this is the required solution.