All categories

3 years ago

Reduction of the amount of waste entering the waste stream is called __________

1 answer:

3 0

The answer that fits the blank is SOURCE REDUCTION. Source reduction refers to the prevention of further pollution by eliminating the source before this can produce the wastes. This helps in the reduction of pollution, thus reduces the amount of toxins brought by these wastes that may harm the environment.

You might be interested in

Help this Is easy for you

DochEvi [55]

Answer:

if its so easy why dont u do it .

Explanation:

6 0

3 years ago

You kick a soccer ball off the ground with a velocity of 15 m/s at an angle of 40° above the horizontal

jeyben [28]

At its maximum height, the ball will have zero vertical velocity, so the ball's velocity at this point is exactly equal to its horizontal velocity.

At any time t, the horizontal component of its velocity is

v = (15 m/s) cos(40°) ≈ 11.49 m/s

so at the highest point of its trajectory, the ball has a velocity of about 11.49 m/s pointed in the positive horizontal direction.

8 0

3 years ago

A particle’s position is ~r = (ct2 − 2dt3 )iˆ+ (2ct2 − dt2 )jˆ, where c and d are positive constants. Find the expressions for t

Mars2501 [29]

The velocity of the particle is given by the derivative of the position vector:

$\vec v = \dfrac{\mathrm d\vec r}{\mathrm dt} = (2ct-6dt^2)\,\vec\imath + (4ct-2dt)\,\vec\jmath$

(a) The particle is moving in the x-direction when the y-component of velocity is zero:

$4ct-2dt = 2t (2c - d) = 0 \implies t=0$

But we want t > 0, so this never happens, unless 2c = d is given, in which case the y-component is always zero.

(b) Similarly, the particle moves in the y-direction when the x-component vanishes:

$2ct-6dt^2 = 2t (c - 3dt) = 0 \implies t=0 \text{ or }c-3dt = 0$

We drop the zero solution, and we're left with

$c-3dt = 0 \implies c=3dt \implies \boxed{t = \dfrac c{3d}}$

In the case of 2c = d, this times reduces to t = c/(6c) = 1/6.

7 0

2 years ago

John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.

aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. $t=6000\ s$ is the total time taken in the trip

c. $d=126000\ m$ is the total distance

d. $s=54000\ m$ towards right from the starting point.

e. $v_a=21\ m.s^{-1}$

f. $\vec v_a=9\ m.s^{-1}$ towards right.

Explanation:

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

Total time of round trip when we're given:

distance travelled to the right, $d_r=90000\ m$

speed while travelling to the right, $v_r=25\ m.s^{-1}$

time spent at gas station, $t_g=600\ s$

time spent while travelling back towards the left, $t_l=30\times 60=1800\ s$

speed while travelling to the left, $v_{_l}=20\ m.s^{-1}$

Now time taken for travelling towards right:

$t_r=\frac{d_r}{v_r}$

$t_r=\frac{90000}{25}$

$t_r=3600\ s$

Therefore total time taken in the round trip:

$t=t_r+t_l+t_g$

$t=3600+600+1800$

$t=6000\ s$

Now, distance travelled towards left:

$d_l=v_{_l}\times t_l$

$d_l=20\times1800$

$d_l=36000\ m$

Therefore total distance:

$d=d_l+d_r$

$d=36000+90000$

$d=126000\ m$

Now, total displacement:

$s=d_r-d_l$

$s=90000-36000$

$s=54000\ m$ towards right from the starting point.

Average speed:

$v_a=\frac{d}{t}$

$v_a=\frac{126000}{6000}$

$v_a=21\ m.s^{-1}$

Average velocity:

$\vec v_a=\frac{s}{t}$

$\vec v_a=\frac{54000}{6000}$

$\vec v_a=9\ m.s^{-1}$ towards right.

4 0

3 years ago

Semi-conductors are materials that

mixas84 [53]

You're right, it is C

6 0

3 years ago

Read 2 more answers