Question

On Planet X, a rock is thrown straight up. The position and velocity of the ball at various times are listed below. (Note: We chose "up" as the "+" direction. What is the acceleration due to gravity on Planet X?

Answer 1

Answer:

$-5.0 m/s^2$

Explanation:

The values of the position and velocity of the ball are missing in the text - found the table in internet, see attached picture.

We can solve this problem by using the following SUVAT equation:

v(t) = u +at

where

v(t) is the velocity of the rock at time t

u is the initial velocity

a is the acceleration of gravity on the planet

t is the time

At t = 0, u = 20 m/s.

After 1 second, t = 1 and v = 15 m/s. Substituting these values and solving for a, we find:

$a=\frac{v-u}{t}=\frac{15-20}{1}=-5.0 m/s^2$

And the negative sign means the acceleration is downward.