Answer:
0.016M
Explanation:
First we find the mole of AgNO3 by using the formula mass/molar mass..
Then we find molarity by the formula mole/volume...
I hope you get this..
Since the beaker was heated we can asume that only magnesium cloride is left in the beaker, therfore the difference between the beaker with magnesium chloride and the empty beaker give the mass of magnisium chloride:
Answer:
I have the same
Explanation:
like I have the same homework as you are u in my class lol?
Answer:
120 g of NaCl in 300 g H20 at 90 C
Explanation:
At x = 90 go vertical to the line for NaCl...then go left to the y-axis to find the solubility in 100 g H20 = 40
we want 300 g H20 so multiply this by 3 to get 120 gm of NaCl in 300 g