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dlinn [17]
3 years ago
14

Air resistance is a fluid type of friction. TRUE OR FALSE

Physics
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

True

Explanation: Air resistance (also called drag) is a type of frictional force. Like all frictional forces, the force of air resistance always opposes the motion of an object. Usually, the air resistance force is not very strong.

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if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second
Vlad [161]

Answer:

   Force required to accelerate = 794.44 N

Explanation:

 Force required = Mass of horse x Acceleration of horse

 Mass of horse and rider, m=   572 kg

 Acceleration of horse and rider, a = 5 kph per second

                                      =\frac{5*1000}{60*60} =1.39 m/s^2

  Force required = ma

                             = 572 x 1.39 = 794.44 N

  Force required to accelerate = 794.44 N

8 0
3 years ago
Please answer me my question​
Angelina_Jolie [31]
3 - b) weight decreases
4 -a) 50 kg as mass is same everywhere
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5 0
3 years ago
What is the magnitude of the acceleration vector which causes a particle to move from velocity −5i−2j m/s to −6i+ 7j m/s in 8 se
shusha [124]

Answer:

Acceleration, a=\dfrac{1}{8}(-i+9j)\ m/s^2

Explanation:

Initial velocity of a particle in vector form, u = (-5i - 2j) m/s

Final velocity of particle in vector form, v = (-6i + 7j) m/s

Time taken, t = 8 seconds

We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{(-6i+7j)\ m/s-(-5i-2j)\ m/s}{8\ s}    

a=\dfrac{(-i+9j)}{8\ s}\ m/s^2    

or

a=\dfrac{1}{8}(-i+9j)\ m/s^2

Hence, the value of acceleration vector is solved.

4 0
4 years ago
~~~~NEED HELP ASAP~~~~
maksim [4K]

the above three pictures may help you

go through the attachments

4 0
3 years ago
Read 2 more answers
Which two statements are true about a system?
shusha [124]
A and c

Because it defines the boundaries of the system
4 0
3 years ago
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