How many moles of CaCI are present in 60.0mL of a 0.10 M CaCI2 solution?

Chemistry

1 answer:

balandron [24]3 years ago

4 0

Answer:

0.006 mol of CaCl2 are present

Explanation:

Use dimensional analysis for this:

60.0 mL CaCl2/1 * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol

If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.

**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.

Hope this helps :)

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The polymer formed from the monomer ch2=ch–cn is select one:

podryga [215]

Answer:
None of the given options show polymer made up of H₂C=CH-CN (Acrylonitrile).

Explanation:
Acrylonitrile (H₂C=CH-CN) which is a monomer on self linkage results in a large chain polymer called as Polyacrylonitrile.
The structure of Polyacrylonitrile is as follow,

--(H₂C-CHCN-)n--

Where n shows the number of Acrylonitrile units joined together in the formation of Polyacrylonitrile. This polymerization reaction can take place by different mechanisms including free radical mechanism, acid catalyzed addition or base catalyzed addition reaction.

The polymerization is shown below,