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igomit [66]
3 years ago
14

How many moles of CaCI are present in 60.0mL of a 0.10 M CaCI2 solution?

Chemistry
1 answer:
balandron [24]3 years ago
4 0

Answer:

0.006 mol of CaCl2 are present

Explanation:

Use dimensional analysis for this:

60.0 mL CaCl2/1  * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol

If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.

**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.

Hope this helps :)

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What does the 4 indicate in 1s22s22p4? 4th subshell 4 electrons 4th energy level
kupik [55]

Answer: The number 4 indicates 4 electrons.

Explanation: We are given an electronic configuration, which is:

1s^22s^22p^4

Here,

  • The letters denote the sub-shells of an element.
  • The numbers written before the letters which are 1, 2 and 2 represents the Principle Quantum Number and these represents the energy level of the sub-shells.
  • The number which are written in the superscripts which are 2, 2 and 4 denotes the electrons which are present in the sub-shell.

Hence, 4 indicates 4 electrons present in 2p sub-shell.

3 0
3 years ago
Read 2 more answers
3.00 L of a gas is collected at 35.0°C and 705.0 mmHg. What is the volume at STP?
makvit [3.9K]

Answer:

2.47L

Explanation:

Using the combined gas law equation as follows:

P1V1/T1= P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 705mmHg

P2 = 760mmHg (STP)

V1 = 3.00L

V2 = ?

T1 = 35°C = 35 + 273 = 308K

T2 = 273K (STP)

Using P1V1/T1= P2V2/T2

705 × 3/308 = 760 × V2/273

2115/308 = 760V2/273

Cross multiply

308 × 760V2 = 2115 × 273

234,080V2 = 577,395

V2 = 577,395 ÷ 234,080

V2 = 2.47L

8 0
2 years ago
Refrigerators are usually kept at about 5°C, while room temperature is about 20°C. if you were to take an empty sealed 2 liter s
MakcuM [25]

Answer:

c) No, because Celsius is not an absolute temperature scale

Explanation:

converting  5 oC to kelvin which is the absolute temperature scale gives = 273 + 5 = 278 K

and converting 20 oC to kelvin = 20 + 273 = 293 K

the ratio = 278 / 293 = 0.94 approx 1 not 4

8 0
3 years ago
Which of the following is not a valid set of quantum numbers
ASHA 777 [7]
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or 

<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.

For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.

The other three sets are valid and can correctly describe an electron.

3 0
2 years ago
Read 2 more answers
A sample of kerosene has a mass of 36.4g. It’s volume is 45.6mL. What is the density of kerosene?
stira [4]

Answer:

<h2>Density = 0.8 g/cm³</h2>

Explanation:

The density of an object can be found using the formula

<h3>Density(\rho) =  \frac{mass}{volume}</h3>

From the question

mass of kerosene = 36.4 g

volume of kerosene = 45.6 mL

To find the density substitute the values into the above formula and solve

We have

<h3>Density =  \frac{36.4}{45.6}</h3>

= 0.7982

We have the final answer as

<h3>Density = 0.8 g/cm³</h3>

Hope this helps you

4 0
3 years ago
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