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Cloud [144]
3 years ago
14

I really need help, dose anybody know the answer?

Physics
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer: no  

Explanation: you add the right side and if it equals the same as the left side then it is balanced.

Anni [7]3 years ago
6 0

no. it is not balanced.

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juin [17]

Answer:

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Explanation:

8 0
3 years ago
Kiara starts at 4, walks 6 blocks left and 2 blocks right. What is her displacement?
d1i1m1o1n [39]
I think 0 because on a number line, left is negative. 4-6=-2. And -2+2 is 0
7 0
3 years ago
Water flows past a flat plate that is oriented parallel to the flow with an upstream velocity of 0.4 m/s. (a) Determine the appr
Trava [24]

Answer:

1.12 m

0.08291 m

Explanation:

u = Upstream velocity = 0.4 m/s

Re = Reynold's number = 5\times 10^5 (turbulent)

\nu = Viscosity of water = 1.12\times 10^{-6}\ Pas

Here the flow is turbulent so we have the relation

Re_{xcr}=\frac{ux_{cr}}{\nu}\\\Rightarrow x_{cr}=\frac{Re_{xcr}\nu}{u}\\\Rightarrow x_{cr}=\frac{5\times 10^5\times 1.12\times 10^{-6}}{0.4}\\\Rightarrow x_{cr}=1.4\ m

The approximate location downstream from the leading edge where the boundary layer becomes turbulent is 1.4 m

Boundary layer thickness relation is given by

\delta={\frac{\nu x}{u}}^{\frac{1}{5}}\\\Rightarrow \delta={\frac{1.12\times 10^{-6}\times 1.4}{0.4}}^{\frac{1}{5}}\\\Rightarrow \delta=0.08291\ m

The boundary layer thickness is 0.08291 m

4 0
4 years ago
Although there are different ways to approach a scientific investigation, all scientific investigations begin with some sort of
Mamont248 [21]

Answer: hypothesis or guess

(pls mark me brainliest)

7 0
4 years ago
Read 2 more answers
help please what is the heat required in kilocalories to convert 2 kg of ice at 0°c completely into steam at 100°c? a. 80 calori
ivann1987 [24]
<span>Q = mL 
</span>
We need to know the latent heat of fusion, L, for 0 degrees.

L = 336 kJ/kg, m = 2kg

where L is the latent heat for vaporization

Q = 2 * 336 = 672 kJ

For conversion between 0 and 100 degree Celsius

Q = mcθ,   specific heat capacity = 4.2 kJ/kgK

Q = 2*4.2* (100 - 0) = 840 kJ

For conversion to steam at 100 degrees Celsius

<span>Q = mL ,  L = latent heat of vaporization = 2256 kj/kg
</span>
Q = 2 * 2256 = 4512 kJ

Total heat = 672 + 840 + 4512 = 6024 kJ

= 6 024 000 J

But 1 calorie = 4.2 J

Therefore 6 024 000 J will be:           6 024 000/4.2 ≈ 1 434 286 Calories

≈ 1 434 kCalories
4 0
3 years ago
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