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3 years ago

Which coordinates best estimates the location of Woonsocket, RI?

Physics

1 answer:

STatiana [176]3 years ago

5 0

Answer:

\43 ° n, 72 ° w

42° 0' 30" N, 71° 30' 58" W

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True or False: A cross product is an equation which states that two ratios are equal.

elena-14-01-66 [18.8K]

I think the answer would be false

6 0

3 years ago

Read 2 more answers

Calculate the force between two objects that have masses of 70 Kilograms and 2,000 kilograms separated by a distance of 1 meter

Hunter-Best [27]

9.3 x 10⁻⁶N

Explanation:

Given parameters:

Mass 1 = 70kg

Mass 2 = 2000kg

distance = 1m

Unknown:

force between them =

Solution:

The force between the two masses will be a gravitational force of attraction.

F = $\frac{G m_{1}m_{2} }{r^{2} }$

G is universal gravitation constant = 6.67430×10−¹¹ N⋅m²/kg²

r is the distance between the two masses

Substituting the parameters:

F = $\frac{6.67 x 10^{-11} x 70 x 2000}{1^{2} }$ = 9.3 x 10⁻⁶N

Learn more:

Universal gravitation constant brainly.com/question/1724648

#learnwithBrainly

5 0

4 years ago

traveling at about 30 mph, how many feet will the average driver cover from the time they see the danger until they hit the brak

barxatty [35]

Answer: 75 ft

Explanation:

Breaking distance = Speed²/ 20

= 30²/20

= 45 feet

Stopping distance = Speed + braking distance

= 30 + 45

= 75 ft

5 0

3 years ago

One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤

OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

$P(t)=60 W, 0\leq t$

$P(t)=25 W, 5.0\leq t$

Aplying the values to the equation we have:

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

$Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}$

$Power_{avg} = 42.5W$

5 0

3 years ago

A light spring of constant 176 N/m rests vertically on the bottom of a large beaker of water.

irakobra [83]

Answer:

14.0 cm

Explanation:

Draw a free body diagram of the block. There are three forces: weight force mg pulling down, elastic force k∆L pulling down, and buoyancy ρVg pushing up.

Sum of forces in the y direction:

∑F = ma

ρVg − mg − k∆L = 0

(1000 kg/m³) (4.63 kg / 648 kg/m³) (9.8 m/s²) − (4.63 kg) (9.8 m/s²) − (176 N/m) ∆L = 0

∆L = 0.140 m

∆L = 14.0 cm

8 0

3 years ago