Work = Force * distance
W = Fd

Given F = 500 N, d = 10 m
W = (500)(10)
W = 5000 J

The work done is 500 Joules. The time of 4 s is irrelevant in this case.

6 0

3 years ago

A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera

lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train = 5.6 x 10⁵kg

Acceleration = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

Force = mass x acceleration

Resultant force that acts on the train is given below;

Force = 5.6 x 10⁵kg x 0.75m/s² = 420000N

7 0

3 years ago

Photons with wavelength 1 pm are incident on electrons. What is the frequency of the Compton-scattered photons at an angle of 60

natali 33 [55]

Answer:

f = 1.354*10^{20} Hz

Explanation:

By conservation of linear momentum, wavelength shift due to collision of photon to electron is given by following formula

$\lambda ^{'}-\lambda =\frac{h}{m_{o}c}(1-cos\theta )$

where h is plank constant = 6.626*10^{-34}

c = speed of light = 3*10^{8} m/s

scattered angle = 60 degree

m = rest mass of electron = 9*10^{-31}

$\lambda ^{'}=10^{-12} +\frac{6.626*10^{-34}}{9*10^{-31}*3*10^{8}}(1-cos60^{o} )$

$\lambda ^{'}= 2.215 pm$

we know that 1 pm = 10^{-12}m

$f = \frac{c}{\lambda ^{'}}$

$f = \frac{3*10^{8}}{2.215 *10^{-12}} = 1.354*10^{20} Hz$

f = 1.354*10^{20} Hz

4 0

3 years ago

LESSON-THE PLANT Fairy

SVEN [57.7K]

A. Tree
B. Shapes
C. Grass
D. Mehndi

6 0

3 years ago