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3 years ago

Which coordinates best estimates the location of Woonsocket, RI?

Physics

1 answer:

STatiana [176]3 years ago

5 0

Answer:

\43 ° n, 72 ° w

42° 0' 30" N, 71° 30' 58" W

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When condensation rates decrease, causing fewer clouds to form, how might humans change their behavior?

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<span>Humans might hold a picnic outside because of a lack of precipitation.</span>

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3 years ago

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As shown in Fig. 4, an ideal gas of monatomic molecules expands from its initial state A to a state B through an isobaric proces

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3 years ago

How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances

Tatiana [17]

Answer:

258774.9441 m

Explanation:

x = Distance of probe from Earth

y = Distance of probe from Sun

Distance between Earth and Sun = $x+y=149.6\times 10^6\ m$

G = Gravitational constant

$M_s$ = Mass of Sun = $1.989\times 10^{30}$

$M_e$ = Mass of Earth = $5.972\times 10^{24}\ kg$

According to the question

$\frac{GM_sm}{x^2}=\frac{GM_em}{y^2}\\\Rightarrow \frac{M_s}{x^2}=\frac{M_e}{y^2}\\\Rightarrow x=\sqrt{\frac{M_s\times y^2}{M_e}}\\\Rightarrow x=\sqrt{\frac{1.989\times 10^{30}\times y^2}{5.972\times 10^{24}}}\\\Rightarrow x=577.10852y$

$x+y=149.6\times 10^6\\\Rightarrow 577.10852y+y=149.6\times 10^6\\\Rightarrow 578.10852y=149.6\times 10^6\\\Rightarrow y=\frac{149.6\times 10^6}{578.10852}\\\Rightarrow y=258774.9441\ m$

The probe should be 258774.9441 m from Earth

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3 years ago

A month ago Jenny was pulled over for speeding and because it was her third ticket this year her license was suspended Jenny jus

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A lesson for her to avoid speeding in the future

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4 years ago

Two students are discussing how the speed of the car compares to the speed of the truck when both vehicles are in front of the h

solniwko [45]

Answer:

a) Student 1 is right in the way he calculates the speed cid d of the truck, since going at constant speed

b) Student 2 is right that for the car to reach the truck it must have some relationship,

c) t = √d/a

Explanation:

In this exercise you are asked to analyze the movement in a mention using kinematics.

a) Student 1 is right in the way he calculates the speed cid d of the truck, since going at constant speed he can use the equation

v = d / t

b) Student 2 is right that for the car to reach the truck it must have some relationship, which is given by

v = v₀ + a t

x = v₀ t + ½ a t²

c) let's use the equations

v = d / t

v = v₀ + at

d / t = vo + at

If we can assume that the car starts from rest, so v₀ = 0

d / t = a t

t² = d / a

t = √d / a

if the speed of the car is not zero the result is a little more complicated

d = vo t + a t²

at² + vo t - d = 0

let's solve the quadratic equation

t = [-v₀ ± √ (v₀² + 4a d)] / 2a

7 0

3 years ago