I don't know this 1 I'm sorry I can't help you
Explanation:
v = wavelength x frequency
330 = 5 . 10-² m x f
f = 6600 Hz
the frequency that human can hear is about 20 Hz - 20000 Hz
so human can hear the note.
Answer:
At 6 minutes, the soil temperature at a 45° angle of insolation is higher than at 0°.
At 15 minutes, the soil temperature at a 90° angle of insolation is higher than at 45°
Explanation:
Integrating the velocity equation, we will see that the position equation is:
![$f(t)=\frac{\cos ^3(\omega t)-1}{3}](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cfrac%7B%5Ccos%20%5E3%28%5Comega%20t%29-1%7D%7B3%7D)
<h3>How to get the position equation of the particle?</h3>
Let the velocity of the particle is:
![$v(t)=\sin (\omega t) * \cos ^2(\omega t)](https://tex.z-dn.net/?f=%24v%28t%29%3D%5Csin%20%28%5Comega%20t%29%20%2A%20%5Ccos%20%5E2%28%5Comega%20t%29)
To get the position equation we just need to integrate the above equation:
![$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cint%20%5Csin%20%28%5Comega%20t%29%20%2A%20%5Ccos%20%5E2%28%5Comega%20t%29%20d%20t)
![$\mathrm{u}=\cos (\omega \mathrm{t})](https://tex.z-dn.net/?f=%24%5Cmathrm%7Bu%7D%3D%5Ccos%20%28%5Comega%20%5Cmathrm%7Bt%7D%29)
Then:
![$d u=-\sin (\omega t) d t](https://tex.z-dn.net/?f=%24d%20u%3D-%5Csin%20%28%5Comega%20t%29%20d%20t)
![\Rightarrow d t=-d u / \sin (\omega t)](https://tex.z-dn.net/?f=%5CRightarrow%20d%20t%3D-d%20u%20%2F%20%5Csin%20%28%5Comega%20t%29)
Replacing that in our integral we get:
![$\int \sin (\omega t) * \cos ^2(\omega t) d t$](https://tex.z-dn.net/?f=%24%5Cint%20%5Csin%20%28%5Comega%20t%29%20%2A%20%5Ccos%20%5E2%28%5Comega%20t%29%20d%20t%24)
![$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$](https://tex.z-dn.net/?f=%24-%5Cint%20%5Cfrac%7B%5Csin%20%28%5Comega%20t%29%20%2A%20u%5E2%20d%20u%7D%7B%5Csin%20%28%5Comega%20t%29%7D-%5Cint%20u%5E2%20d%20t%3D-%5Cfrac%7Bu%5E3%7D%7B3%7D%2Bc%24)
Where C is a constant of integration.
Now we remember that ![$u=\cos (\omega t)$](https://tex.z-dn.net/?f=%24u%3D%5Ccos%20%28%5Comega%20t%29%24)
Then we have:
![$f(t)=\frac{\cos ^3(\omega t)}{3}+C](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cfrac%7B%5Ccos%20%5E3%28%5Comega%20t%29%7D%7B3%7D%2BC)
To find the value of C, we use the fact that f(0) = 0.
![$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cfrac%7B%5Ccos%20%5E3%28%5Comega%20%2A%200%29%7D%7B3%7D%2BC%3D%5Cfrac%7B1%7D%7B3%7D%2BC%3D0)
C = -1 / 3
Then the position function is:
![$f(t)=\frac{\cos ^3(\omega t)-1}{3}](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cfrac%7B%5Ccos%20%5E3%28%5Comega%20t%29-1%7D%7B3%7D)
Integrating the velocity equation, we will see that the position equation is:
![$f(t)=\frac{\cos ^3(\omega t)-1}{3}](https://tex.z-dn.net/?f=%24f%28t%29%3D%5Cfrac%7B%5Ccos%20%5E3%28%5Comega%20t%29-1%7D%7B3%7D)
To learn more about motion equations, refer to:
brainly.com/question/19365526
#SPJ4
Answer:
1. Energy = 2880 Joules.
2. Energy = 60 Joules.
3. Quantity of charge = 120 Coulombs.
Explanation:
Given the following data;
1. Voltage = 12 Volts
Current = 0.5 Amps
Time, t = 8 mins to seconds = 8 * 60 = 480 seconds
To find the energy;
Power = current * voltage
Power = 12 * 0.5
Power = 6 Watts
Next, we find the energy transferred;
Energy = power * time
Energy = 6 * 480
Energy = 2880 Joules
2. Charge, Q = 4 coulombs
Potential difference, p.d = 15V
To find the total energy transferred;
Energy = Q * p.d
Energy = 4 * 15
Energy = 60 Joules
3. Voltage = 6 Volts
Current = 1 Amps
Time = 2 minutes to seconds = 2 * 60 = 120 seconds
To find the quantity of charge;
Quantity of charge = current * time
Quantity of charge = 1 * 120
Quantity of charge = 120 Coulombs