Answer:
Tension in cable BE= 196.2 N
Reactions A and D both are 73.575 N
Explanation:
The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence
hence
Therefore, tension in the cable,
Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then
Similarly,
Therefore, both reactions at A and D are 73.575 N
24Ω
<h2>Explanation:</h2>
When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.
For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;
=
+
Solving for Rₓ gives;
=
------------------(i)
From the question;
Let
R₁ = resistance of first resistor = 40Ω
R₂ = resistance of second resistor = 60Ω
Now,
To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;
=
=
= 24 Ω
Therefore, the total resistance is 24Ω